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kherson
2 months ago
9

A carbene is a highly reactive intermediate in which a carbon atom bears a lone pair and no formal charge: how many hydrogen ato

ms are attached to the central carbon atom above?
Chemistry
1 answer:
lorasvet [2.7K]2 months ago
4 0

Carbene  is defined as CH₂ (methylene), featuring a neutral divalent carbon atom with a valency of two and possessing two unshared valence electrons. There are two varieties of carbenes: singlet and triplet. Carbenes tend to have a very brief existence and are quite unstable, acting as highly reactive intermediates. The typical carbene, which specifically denotes methylene (:CH₂), has two hydrogen atoms attached. Carbenes play a crucial role as intermediates in various organic synthesis processes.

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What is the emperical formula for a compound containing 68.3% lead, 10.6% sulfur, and the remainder oxygen? a. Pb2SO4 b. PbSO3 c
Tems11 [2777]

Solution:

The molecular formula is PbSO₄, indicating lead sulfate

Option c.

Explanation:

The percentage makeup shows that in 100 g of this compound, there are:

68.3 g of Pb, 10.6 g of S, and (100 - 68.3 - 10.6) = 21.1 g of O

To find the moles of each element, we divide by their molar masses:

68.3 g Pb / 207.2 g/mol = 0.329 moles Pb

10.6 g S / 32.06 g/mol = 0.331 moles S

21.1 g O / 16 g/mol = 1.32 moles O

Next, we find the mole ratio by dividing each by the smallest number of moles:

0.329 / 0.329 = 1 Pb

0.331 / 0.329 = 1 S

1.32 / 0.329 = 4 O

Thus, the molecular formula is PbSO₄, representing lead sulfate.

8 0
2 months ago
Read 2 more answers
Calculate the ratio of the velocity of helium atoms to the velocity of neon atoms at the same temperature.
Tems11 [2777]

Answer:

vHe / vNe = 2.24

Explanation:

To determine the velocity of an ideal gas, one should apply the formula:

v = √3RT / √M

In this equation, R represents the gas constant (8.314 kgm²/s²molK); T refers to temperature, and M indicates the molar mass of the gas (4x10⁻³kg/mol for helium and 20.18x10⁻³ kg/mol for neon). Hence:

vHe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol

vNe = √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

The ratio simplifies to:

vHe / vNe = √3×8.314 kgm²/s²molK×T / √4x10⁻³kg/mol / √3×8.314 kgm²/s²molK×T / √20.18x10⁻³kg/mol

vHe / vNe = √20.18x10⁻³kg/mol / √4x10⁻³kg/mol

vHe / vNe = 2.24

I hope it assists you!

8 0
2 months ago
If 3.8 kcal is released by combustion of each gram of glucose, how many kilocalories are released by the combustion of 1.50 mol
castortr0y [3046]
684 kcal. One mole of glucose weighs roughly 180g. Given that 1g of glucose releases 3.8 kcal, we calculate for 1 mole of glucose: 180g -> 180g * 3.8 kcal/g = 684 kcal.
7 0
2 months ago
Which items in this image are electrically conductive? Check all that apply.
Anarel [2989]
A indicates the power lines are what truly conducts (or transmits) the power.
Options B or E are incorrect, as wood is not a good conductor. That's why it's commonly used in homes to retain heat (which comes from electricity), preventing it from escaping.
Option C is also not correct since rubber, similarly, is a poor conductor. Like wood, it acts as an insulator, not transmitting heat (or electricity). This is why rubber gloves are utilized during electrical work.
Option D is valid—most metals are excellent electricity conductors. For instance, copper pans are efficient in cooking because copper effectively conducts heat. Being a metal, this is also why wire cutters have rubber grips; it isolates the user from potential electric shock from the conductive metal. The rubber serves as a barrier to protect against electrocution when handling wires or electricity.
3 0
1 month ago
Read 2 more answers
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