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Mandarinka
3 months ago
11

Lin created a scaled copy of Triangle A with an area of 72 square units. How many times larger is the area of the scaled copy co

mpared to that of Triangle A

Mathematics
2 answers:
PIT_PIT [12.4K]3 months ago
6 0

Answer:

The question appears to be incomplete, here’s a possible interpretation of the full question:

Here is Triangle A. Lin produced a scaled version of Triangle A with an area of 72 square units. What scale factor was used by Lin to create this copy? Recall: A=1/2bh

a) 4

b) 8

c) 16

Answer:

Scale factor = 16

Step-by-step explanation:

Based on the diagram provided, the triangle was drawn on graph paper, where each grid equals 1 unit. Thus, the dimensions of Triangle A derived from the diagram are:

Base = 3 units

Height = 3 units

To find the scale factor associated with the area of the triangle after scaling, we first calculate the area of the original triangle.

Area of Triangle = 1/2 (base × height)

Area of Triangle = 0.5 × 3 × 3 = 4.5 square units

Consequently,

Area of the original triangle = 4.5 square units

Area of the scaled triangle = 72 square units

Since the area of the scaled triangle exceeds that of the original, the scale factor simply reflects how many times the area was increased from the original triangle to the scaled one, calculated as:

Scale factor = (scaled triangle) ÷ (original triangle)

Scale factor = 72 ÷ 4.5 = 16

Leona [12.6K]3 months ago
0 0

What is the proportion by which the area of the scaled version is larger compared to Triangle A?

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Zucchini weights are approximately normally distributed with mean 08 pound and standard deviation 0.25 pound. Which of the follo
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The correct answer is A. According to the question's details, we're provided with key statistics on zucchini weights, which suggest that the average turns out to be typically 0.8 pounds, while the standard deviation is noted as 0.25 pounds. The probability of a randomly selected zucchini weighing between 0.55 pounds and 1.3 pounds can be mathematically expressed. Observing the provided normal distribution options, option A aligns with our specified weight range.
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1 month ago
6a−3b=5b solve for a:b ratio plz help
babunello [11817]

Add 3b to both sides, then simplify. Next, divide both sides by 6 and simplify it further, leading to the result of a = 4b/3.

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3 months ago
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On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl
lawyer [12517]

Answer:

0.40

Step-by-step explanation:

The percentage of members who engage only in long-distance running is 8%

Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08

The percentage of members who participate exclusively in field events is 32%

Thus, the probability of a member competing only in field events is P(B) = 0.32

The percentage of members acting as sprinters is 12%

So, the probability that a member is a sprinter is P(C) = 0.12

We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:

P(A or B) = P(A) + P(B)

Substituting the known values results in:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40

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2 months ago
Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Svet_ta [12734]

It's known that

When two lines are parallel, their slopes are identical.

The slope between any two points can be calculated using the following formula:


m=\frac{y2-y1}{x2-x1}


We will calculate the slope for each case to find the solution to the problem.

Case A) Point B(5,2)\ C(7,-5)

Determine the slope of BC

Insert the values into the formula:

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


Thus,

The equation y=-3.5x-15 is parallel to the line that goes through the points B(5,2)\ C(7,-5)

Therefore,

the result for Part A) is

B(5,2)\ C(7,-5) ------> y=-3.5x-15

Case B) Point D(11,6)\ E(5,9)

Calculate the slope of DE

Plug the values into the formula:

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


Thus,

The equation y=-0.5x-3 is parallel to the line that goes through the points D(11,6)\ E(5,9)

Therefore,

the result for Part B) is

D(11,6)\ E(5,9) ------> y=-0.5x-3

Case C) Point F(-7,12)\ G(3,-8)

Determine the slope of FG

Insert the values into the formula:

m=\frac{-8-12}{3+7}

m=\frac{-20}{10}


m=-2


Thus,

Any linear equation with slope m=-2 will be parallel to the line through the points F(-7,12)\ G(3,-8)

Case D) Point H(4,4)\ I(8,9)

Calculate the slope of HI

Substitute the values in the formula:

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


Thus,

The equation y=1.25x+4 is parallel to the line through the points H(4,4)\ I(8,9)

Therefore,

the result for Part D) is

H(4,4)\ I(8,9) ------> y=1.25x+4

Case E) Point J(7,2)\ K(-9,8)

Determine the slope of JK

Insert the values into the formula:

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


Thus,

Any linear equation characterized by slope m=-0.375 will be parallel to the line that runs through the points J(7,2)\ K(-9,8)

Case F) Point L(5,-7)\ M(4,-12)

Find the slope of LM

Substitute the values in the formula:

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


Thus,

The equation y=5x+19 is parallel to the line connecting the points L(5,-7)\ M(4,-12)

Therefore,

the result for Part F) is

L(5,-7)\ M(4,-12) ------> y=5x+19




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3 months ago
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