Let X be the amount of 90% alloy and Y be the amount of 70% alloy. The equations are: x + y = 60 0.9x + 0.7y = 0.85 * 60 By substituting, we have: 0.9x + 0.7(60 - x) = 0.85 * 60 This simplifies to: (0.9 - 0.7)x = (0.85 - 0.7)*60 Solving for x yields: x = (0.85 - 0.7)*60/(0.9 - 0.7) x = 45 ounces For Y, we find: y = 60 - 45 y = 15 ounces
Answer:
Explanation:
Hello!
You possess a sample involving 200 participants, who were surveyed regarding their main source of news, categorized into (1) Television, (2) Radio, (3) Internet, and (4) Other.
Your goal is to evaluate whether the proportions in this sample align with the established frequencies of 10%, 30%, 50%, and 10% respectively.
The suitable statistical method to assess if the sample matches the known or historical distribution is the Chi-Square goodness of fit test. In this test, the null hypothesis represents the model or distribution under examination. In this scenario, you need to articulate the proportions for each category:
H₀: P(1)= 0.10; P(2)= 0.30; P(3)= 0.50; P(4)= 0.10
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Utilize the! operation to determine the count of combinations.
8!/5! = 40,320/120 = 336