Answer:
0.012 km/hr
Step-by-step explanation:
(1200 cm)(1 m/100 cm)(1 km/1000 m) = 0.012 km/hr
Answer:
60
Step-by-step explanation:
The function provided is:
The average rate of change of h(t) as time goes from t=a to t=b is expressed as:
This function can be reformulated as: 
The rocket's peak height is 231, which occurs at t=3.75 seconds.
The initial launch happens at: t=0
and 
The average rate of change from launch to max height is
Answer:
5.25ft below the waterline
Step-by-step explanation:
1. I entered the given equation into a graphing calculator (I use Desmos) and substituted "t" with "x" since it’s easier that way.
2. A graph appeared. To find the initial position of the paddle, I checked where it was at t=0, which is the y-intercept. It shows it’s at -5.25, indicating it sits 5.25 below the surface of the water.
<span>The system of equations that can determine if the commuter jet’s flight path crosses the restricted airspace is:
y = \frac{1}{4}(x - 10)^2 + 6 (i)
y = \frac{-27}{34}x - \frac{5}{17} (ii)
</span><span>
Here's why:
</span><span>
The closed airspace boundary is defined by points (10, 6) and (12, 7).
</span>
The commuter jet’s linear path runs from (-18, 14) to (16, -13).
Equation (i) describes the boundary since it fits both (10, 6) and (12, 7):
For (10, 6):
\frac{1}{4}(10-10)^2 + 6 = 6 (true)
For (12, 7):
\frac{1}{4}(12-10)^2 + 6 = 1 + 6 = 7 (true)
Equation (ii) represents the commuter jet’s path as it fits both (-18, 14) and (16, -13):
For (16, -13):
-13 = \frac{-27}{34} \times 16 - \frac{5}{17} = -13 (true)
For (-18, 14):
14 = \frac{-27}{34} \times (-18) - \frac{5}{17} = 14 (true)
By solving this system, we can confirm that the jet’s flight path intersects the closed airspace.
4.2x - 1.4y = 2.1
-1.4y = 2.1 - 4.2x
y = \frac{2.1 - 4.2x}{-1.4}
y = 3x - 1.5 <==
