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LekaFEV
9 days ago
9

The probability that an individual is left-handed is 0.12. in a class of 39 students, what is the probability of finding five le

ft-handers
Mathematics
2 answers:
Svet_ta [12.2K]9 days ago
8 0

We start with the following information:

p = probability = 0.12<span>
n = total number of students = 39 </span>

x = number of left-handers = 5<span>
u = mean = p * n = 4.68
σ = standard deviation = √(n*p*(1-p)) = √(39 * 0.12 * 0.88) = 2.03</span>

Finding the z score:

z = (x – u) / σ

<span> z = (5 – 4.68) / 2.03
</span>

z = 0.1576 = 0.16

<span>

</span>Applying standard tables for z gives the p value as:

p value = 0.5636 = 56.36%

 

Consequently, there is a 56.36% probability.

 

Inessa [12.1K]9 days ago
6 0

Response:

0.1856

Step-by-step breakdown:

The probability of a person being left-handed is 0.12.

n = total number of students = 39

q = 1-p = 0.88

Let X denote the number of left-handed students.

X is binomial since each student acts independently with only two possible outcomes

X:Bin(39, 0.12)

Calculating the probability of finding five left-handers

P(X=5) = 39C5 (0.12)^5 (0.88)^34

= 0.1856

The result is 0.1856

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