The probability that an individual is left-handed is 0.12. in a class of 39 students, what is the probability of finding five le

Question

1 month ago

9

ft-handers

2 answers:

Svet_ta [12.7K] · Answer 1 · 2026-03-31T04:38:28+03:00

We start with the following information:

p = probability = 0.12
n = total number of students = 39

x = number of left-handers = 5
u = mean = p * n = 4.68
σ = standard deviation = √(n*p*(1-p)) = √(39 * 0.12 * 0.88) = 2.03

Finding the z score:

z = (x – u) / σ

z = (5 – 4.68) / 2.03

z = 0.1576 = 0.16

Applying standard tables for z gives the p value as:

p value = 0.5636 = 56.36%

Consequently, there is a 56.36% probability.

Inessa [12.5K] · Answer 2 · 2026-03-31T04:37:59+03:00

Response:

0.1856

Step-by-step breakdown:

The probability of a person being left-handed is 0.12.

n = total number of students = 39

q = 1-p = 0.88

Let X denote the number of left-handed students.

X is binomial since each student acts independently with only two possible outcomes

X:Bin(39, 0.12)

Calculating the probability of finding five left-handers

P(X=5) = 39C5 (0.12)^5 (0.88)^34

= 0.1856

The result is 0.1856