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lisabon 2012
2 months ago
5

The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil

e range of the data?
2
3
4
6
Mathematics
2 answers:
Leona [12.6K]2 months ago
4 0
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, presented in ascending order
Q2 (median) = d5 = 2 //middle value
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 represents the median of d1,d2,d3,d4, but as there is no singular middle element among four, the average is computed)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquartile range = IQR = Q3 - Q1 = 5 -1 = 4
final answer: 4

Leona [12.6K]2 months ago
4 0

Answer:

Option C.

Step-by-step explanation:

The provided data set is

0, 2, 4, 0, 2, 3, 2, 8, 6

Rearranging the data in ascending order gives:

0, 0, 2, 2, 2, 3, 4, 6, 8

Next, the data set is divided into four equal segments.

(0, 0), (2, 2), 2, (3, 4), (6, 8)

Now, we see:

Q_1=\dfrac{0+2}{2}=1

Q_2=Median=2

Q_3=\dfrac{4+6}{2}=5

The formula for the interquartile range:

IQR=Q_3-Q_1

IQR=5-1

IQR=4

Thus, the interquartile range calculated is 4, making option C correct.

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