Eddie is practicing wind sprints during his summer break. He's able to run 72 meters in 12 seconds. If d represents distance and

12 m^2/h to cm^2/min

12 m^2/h × 1 h/60 min = 0.2 m^2/min

0.2 m^2/min × 10000 cm^2/1 m^2 = 2000 cm^2/min

2000 cm^2/min

El cuadro de proporciones debe reflejar dimensiones que sean comparables a las del rectángulo original. Es decir, las medidas de los rectángulos adicionales deben multiplicarse por un factor de escala para hacer el aumento. Revisé cada medida para confirmar si era un múltiplo del rectángulo original.

Question 1: (2.2, -1.4). Question 2: (1.33, 1). Providing a detailed analysis, the equations for the given lines are specified as (1) passing through points (0, 2.5) and (2.2, 1.4), and (2) through (0, -3) and (2.2, -1.4). We are tasked with locating a common solution or intersection of these equations. This leads to finding x = 2.2, and consequently y = -1.4. Therefore, the solution set is (2.2, -1.4). For question 2, the equations yield a solution of (1.33, 1).

Answer: After the withdrawal, Rajan's bank balance will be

6150 RS - 2050 RS = 4100 RS

Step-by-step explanation:

Initially, Rajan had 6000 RS in his bank account about a week ago. This indicates that the initial balance he possessed is 6000 RS.

One week later, he credited 150p RS to his account.

Thus, the current total in his account is

= 6000 RS + 150p RS = 6150 RS.

The following day, he withdrew one-third of his total balance. Therefore, the amount withdrawn is

1/3 × 6150 = 6150/3 = 2050 RS

After the withdrawal, his remaining balance in the bank will be the new total minus the amount withdrawn.

His remaining balance in the bank account post-withdrawal will be

6150 RS - 2050 RS = 4100 RS

A right triangle will have 2.2 km as its hypotenuse, with an angle of 0.5 degrees and an unknown height (see attachment).

Remember to apply the trigonometric ratios: sine, cosine, and tangent for right triangles.
Sin<span>θ = opposite side/hypotenuse
</span>Cos<span>θ = adjacent side/hypotenuse
</span>tan<span>θ = opposite side / adjacent side
</span>In this scenario, θ signifies the angle (not the right angle), which is given as 0.5°.

For this problem, we use sine as we have the side opposite the angle (the unknown height h) and the hypotenuse, with sine relating these two sides.

Let h represent the unknown opposite side, the height.
sin(0.5°) = h / (2.2km)
h = (2.2km)sin(0.5<span>°)
h = 0.019 km

I hope this has clarified your question! If you need clarification on any steps, please ask below.</span>