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RSB
4 months ago
10

The maximum mass the can be hung vertically from a string without breaking the string is 10kg. A length of this string that is 2

m long is used to rotate a 0.5kg object in a circle on a frictionless table with the string horizontal. The maximum speed that the mass can attain under these conditions without the string breaking is most nearly:
Answer is 20 m/s
Please show me how I can get the answer. Thank you.
Physics
1 answer:
serg [3.5K]4 months ago
0 0

Respuesta:

Explicación:

Al analizar esta pregunta, considera el movimiento circular. Primero, determina la máxima fuerza que puede aplicarse al hilo. F = mg, entonces F = (10)(10) = 100 N. Luego, calcula la aceleración centrípeta de la masa de 0.5 kg, a = F/m, así que a = 100/.5 = 200 m/s². En la hoja de ecuaciones, usa la fórmula a (aceleración centrípeta) = v²/r, por lo que 200 = v²/2; por consiguiente, v = 20 m/s. ¡Espero que esto sea útil!

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Two identical balls are at rest and side by side at the top of a hill. You let one ball, A, start rolling down the hill. A littl
inna [3103]

Answer:

Option b. it has the same position and the same acceleration as A

Explanation:

Now, let's examine each statement:

a. it has the same position and the same velocity as A

At the moment B overtakes A, they share the same location. However, their velocities cannot match, or else ball B wouldn't be able to pass ball A. Thus, this statement is false.

b. it has the same position and the same acceleration as A

As established before, their positions coincide, and both balls are subjected to gravitational acceleration, making this statement true.

c. it has the same velocity and the same acceleration as A

While the accelerations are identical, their velocities differ, rendering this statement false.

d. it has the same displacement and the same velocity as A

Though they have traveled the same distance, their velocities are not the same, thus this statement is false.

e. it has the same position, displacement and velocity as A

While their position and displacement match, their velocities do not, so this statement is false.

Therefore, only option b is correct.

3 0
3 months ago
A metal, M, forms an oxide having the formula M2O3 containing 52.92% metal by mass. Determine the atomic weight in g/mole of the
ValentinkaMS [3465]

Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

  • 52.92% metal: 52.92 g M
  • 47.80% oxygen: 47.80 g O

 By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=\frac{47.8g*1mol}{16g}

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass=\frac{52.92 g}{5.975 mol}

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

3 0
3 months ago
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