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xenn
4 days ago
14

Two identical balls are at rest and side by side at the top of a hill. You let one ball, A, start rolling down the hill. A littl

e later you start the second ball, B, down the hill by giving it a shove. The second ball rolls down the hill along a line parallel to the path of the first ball and passes it. At the instant ball B passes ball A:
a. it has the same position and the same velocity as A.b. it has the same position and the same acceleration as A.c. it has the same velocity and the same acceleration as A.d. it has the same displacement and the same velocity as A.e. it has the same position, displacement and velocity as A.
Physics
1 answer:
inna [2.2K]4 days ago
3 0

Answer:

Option b. it has the same position and the same acceleration as A

Explanation:

Now, let's examine each statement:

a. it has the same position and the same velocity as A

At the moment B overtakes A, they share the same location. However, their velocities cannot match, or else ball B wouldn't be able to pass ball A. Thus, this statement is false.

b. it has the same position and the same acceleration as A

As established before, their positions coincide, and both balls are subjected to gravitational acceleration, making this statement true.

c. it has the same velocity and the same acceleration as A

While the accelerations are identical, their velocities differ, rendering this statement false.

d. it has the same displacement and the same velocity as A

Though they have traveled the same distance, their velocities are not the same, thus this statement is false.

e. it has the same position, displacement and velocity as A

While their position and displacement match, their velocities do not, so this statement is false.

Therefore, only option b is correct.

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A spin bike has a flywheel in two parts—a 12.5 kg disk with radius 0.23 m, and a 7.0 kg ring with mass concentrated at the outer
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Response:

Clarification:

Provided

weight of disk m=12.5 kg

diameter of disc R=0.23 m

weight of ring m_r=7 kg

Force F=9.7 N

N=180 rpm

\omega =\frac{2\pi N}{60}

\omega =6\pi rad/s

Overall moment of inertia

=Disc's moment of inertia +Ring's Moment of Inertia

=0.5\cdot 12.5\times 0.23^2+7\times 0.23^2

=13.25\times 0.23^2=0.7009 kg-m^2

At this point, Torque is T=F\times R=I\cdot \alpha

9.7\times 0.23=0.7\times \alpha

\alpha =3.18 rad/s^2

Utilizing \omega _f=\omega +\alpha t

\omega _f=0 in this scenario

0=6\pi -3.18\times t

t=\frac{6\pi }{3.18}

t=5.92 s

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1 day ago
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1. A U.S. manufacturer wants to sell computer equipment to companies in Honduras. Because the U.S. government limits trade with
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If the U.S. government prohibits the manufacturer from exporting their products to Honduras, the manufacturer will forfeit the non-refundable application fee of $2,700. Additionally, due to the restrictions on trade with Honduras, the manufacturer must secure an export license from the Department of Commerce, potentially leading to reduced demand for U.S. goods. Furthermore, the total value of product exports must reach at least $10,800 while the license is active to justify the application and licensing fees.
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A particle has a charge of -4.25 nC.
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Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

The electric field can be calculated using

E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C

The calculated magnitude is 611.32 N/C

The electric field direction is vertically downward due to the negative charge.

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The distance from the electric field source is 1.71436 m

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1 month ago
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