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Paha777
4 days ago
8

Two rigid rods are oriented parallel to each other and to the ground. The rods carry the same current in the same direction. The

length of each rod is 1.1 m, while the mass of each is 0.11 kg. One rod is held in place above the ground, and the other floats beneath it at a distance of 8.3 mm. Determine the current in the rods.

Physics
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1. A 930-kg car traveling 56 km/h comes to a complete stop in 2.0 s. What is the
kicyunya [3294]
The force exerted on the car during the stop measures 6975 N. Explanation: Given that the mass (m) is 930 kg, speed (s) at 56 km/h converts to 15 m/s, and the stopping time (t) is 2 s, we compute the force using F = m * a. Here, acceleration (a) can be obtained through a = s/t. The total force calculation confirms that F = 930 kg * (15 m/s) / 2 s results in 6975 N.
6 0
1 month ago
A student is trying to classify an unidentified, solid gray material as a metal or a nonmetal. Which question will best help the
kicyunya [3294]
The most effective question for the student to determine whether the substance is metal or nonmetal would be option C.
8 0
1 month ago
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A hiker walks 200m west and then walks 100m north. What is the magnitude and direction of her resulting displacement?
Maru [3345]

A hiker proceeds 200 m west and subsequently another 100 m north, resulting in a displacement of 223 m. The direction can be determined using the trigonometric function where sin(angle) = opposite/hypotenuse, yielding an angle of 26.6 degrees. Therefore, the total displacement is 223 m at an angle of 26.6 degrees north of west.

7 0
2 months ago
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In 2014, the Rosetta space probe reached the comet Churyumov Gerasimenko. Although the comet's core is actually far from spheric
ValentinkaMS [3465]

To tackle this issue, we will utilize concepts related to gravity based on Newtonian definitions. To find this value, we'll apply linear motion kinematic equations to determine the required time. Our parameters include:

Comet mass M = 1.0*10^{13} kg

Radius r = 1.6km = 1600 m

The rock is released from a height 'h' of 1 m above the surface.

The relationship for gravity's acceleration concerning a body with mass 'm' and radius 'r' is described by:

g = \frac{GM}{R^2}

Where G represents the gravitational constant and M denotes the mass of the planet.

g = \frac{(6.67408*10^{-11})(1*10^{13})}{1600^2}

g = 2.607*10^{-4} m/s^2

Now, let’s compute the time value.

h = \frac{1}{2} gt^2

t = \sqrt{\frac{2h}{g}}

t = \sqrt{\frac{2(1)}{2.607*10^{-4}}}

t = 87.58s

Ultimately, the time for the rock to hit the surface is t = 87.58s.

8 0
2 months ago
A runner runs 4875 ft in 6.85 minutes. what is the runners average speed in miles per hour?
Keith_Richards [3271]

Calculating the average speed is straightforward by using the formula involving distance and time:

average speed = distance / time

 

Thus, we have:

average speed = 4875 ft / 6.85 minutes

<span>average speed = 711.68 ft / min</span>

8 0
3 months ago
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