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kykrilka
8 days ago
5

According to the manufacturer, about 26% of sour candy in a package of Sandy's Sours are grape. What is the probability that the

first grape candy chosen from the bag will be, at LEAST, the third candy chosen overall?
Mathematics
2 answers:
Inessa [12.1K]8 days ago
8 0

Response:

1/ 50 x 33 x 98 x 26

= 1/4204200

Step-by-step clarification: 1/ 50 x 33 x 98 x 26

= 1/4204200

Zina [11.9K]8 days ago
8 0

Response:


Step-by-step explanation:

Assuming there are 100 sour candies, thus-  

since 26% of the candies are grape, it follows that 26% of 100 candies means we have 26 grape candies

Consequently, the remaining candies that are not grape amount to 100-26 = 74

Applying the multiplication principle:

P(A ∩ B) = P(A)/ P(B|A)  

 Initially, there are 26 grape candies, therefore the probability of selecting the first grape candy =  26C1 = 26

 After choosing the first one, we put the selected grape candy back, so there are still 100 candies total P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!

= 50 x 33 x 98

Thus, the probability becomes 1/ 50 x 33 x 98 x 26

= 1/4204200

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