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ira
4 days ago
7

_______________ is used by a hacker to mask intrusion and obtain administrator permissions to a computer.

Computers and Technology
1 answer:
Amiraneli [921]4 days ago
6 0
The term you're looking for is Rootkit. This refers to a suite of software tools, primarily malicious, that hackers utilize to gain administrative access to a system while concealing their presence.
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#Write a function called "angry_file_finder" that accepts a #filename as a parameter. The function should open the file, #read i
ivann1987 [930]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

7 0
6 days ago
You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation
ivann1987 [930]

Response: explained in the explanation section

Explanation:

Given that:

Assume D(k) =║ true if [1::: k] is a valid sequence of words, or false otherwise

  • In determining D(n)

the sub problem s[1::: k] is a valid sequence of words IFF s[1::: 1] is valid and s[ 1 + 1::: k] is a valid word.

Thus, we derive that D(k) is defined by the following recurrence relation:

D(k) = ║ false max(d[l] ∧ DICT(s[1 + 1::: k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1::: k]             ∦ array of boolean variables.

for a ← 1 to m

do;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1::: a])

d (a) ← True

(b). Algorithm Output

      if D[k] == True

stack = temp stack            ∦stack assists in displaying the strings in order

c = k

while C > 0

stack push (s [w(c)]::: C] // w(p) denotes the index in s[1::: k] of the valid word // at position c

P = W (p) - 1

output stack

= 0 =

cheers, I hope this aids you!!!

8 0
16 days ago
Which decimal value (base 10) is equal to the binary number 1012?
Natasha_Volkova [897]

Answer:

The decimal representation of 101₂² from base 2 equals 25 in base 10.

Explanation:

To derive the decimal equivalent of 101₂²;

101₂ × 101₂ results in 101₂ + 0₂ + 10100₂.

In this expression, we observe that the '2' in the hundred's place must be converted to '0' while carrying over '1' to the thousand's position, leading to;

101₂ + 0₂ + 10100₂ = 11001₂.

This shows that;

101₂² =  11001₂.

Next, we convert the outcome of squaring the base 2 number, 11001₂, into base 10 through the following method;

Converting 11001₂ to base 10 results in;

1 × 2⁴ + 1 × 2³ + 0 × 2² + 0 × 2¹ + 1 × 2⁰.

The calculation yields;

16 + 8 + 0 + 0 + 1 = 25₁₀.

7 0
1 month ago
A retailer is able to track which products draw the most attention from its customers through the use of 5g-enabled motion senso
zubka84 [942]

The technology that integrates with 5g capabilities for tracking shopping trends is known as the internet of things.

To clarify, let's define internet of things.

  • The internet of things refers to a network of Internet-enabled objects, often utilizing web services for interaction.
  • There has been a notable development in the Internet where devices maintain network connectivity, allowing them to transmit and receive data.

Based on this explanation, we can affirm that the assertion regarding the technology using 5g capabilities for monitoring shopping behaviors being labeled as internet of things is accurate.

Find out more about internet of things here:

7 0
28 days ago
Determine the number of bytes necessary to store an uncompressed binary image of size 4000 × 3000 pixels
maria [879]

Response: 1,500,000 bytes.

Clarification:

If we assume the image dimensions are 4000 pixels in width and 3000 pixels in height, the total uncompressed image will consist of 4000*3000= 12,000,000 pixels.

In the case of a binary image, each pixel can have only two values, which necessitates one bit for each pixel.

This indicates that we need to accommodate 12,000,000 bits.

Given that 1 byte equals 8 bits.

So, to store an uncompressed binary image sized 4000 x 3000 pixels, 12,000,000/8 bytes is required ⇒ 1,500,000 bytes.

3 0
26 days ago
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