The same physics student jumps off the back of her Laser again, but this time the Laser is
2 answers:
a) The student's speed after jumping is 1.07 m/s
b) The final speed of the laser is 10.4 m/s
Explanation:
a)
This issue can be approached through the momentum conservation principle: In the absence of external forces, the combined momentum of the student and the laser must remain unchanged. Hence, we can express:
where:
The initial momentum is zero
m = 42 kg signifies the mass of the laser
v = 1.5 m/s is the laser's final velocity
M = 59 kg is the mass of the student
V denotes the student's final velocity
Solving this for V, we can determine the student's speed:
Thus, the student's final speed calculates to 1.07 m/s.
b)
Here, both the laser and the student have a combined speed of 3.1 m/s prior to the student's jump; thus, the initial momentum isn't zero.
<pSo, we formulate the equation of momentum conservation as:where:
m = 42 kg denotes the mass of the laser
M = 59 kg is the student’s mass
u = 3.1 m/s is their starting velocity
V = -2.1 m/s indicates the student's speed post-jump (she jumps backward)
v signifies the laser's final speed
When we resolve for v, we have:
Learn more about momentum:
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Response:
Once it has crossed, the locomotive requires 17.6 seconds to achieve a speed of 32 m/s.
Details:
The locomotive's acceleration is 1.6
The duration taken to pass the crossing is 2.4 seconds.
We can apply the motion equation, v = u + at, where v represents final velocity, u indicates initial velocity, a denotes acceleration, and t signifies time.
When the speed reaches 32 m/s, we have v = 32 m/s, u = 0 m/s, and a= 1.6 .
32 = 0 + 1.6 * t
t = 20 seconds.
Therefore, the locomotive attains a speed of 32 m/s after 20 seconds, and it passes the crossing in 2.4 seconds.
Thus, after clearing the crossing, it takes an additional 17.6 seconds to reach the speed of 32 m/s.