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Jet001
10 days ago
9

If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is

Physics
2 answers:
Sav [2.2K]10 days ago
8 0
The weight of the woman in pounds equals 125 lb
1 kg outweighs 1 pound, and 1 kilogram equals approximately 2.20462 pounds.  
Thus, converting 125 lb results in 125 / 2.20462 kilograms = 56.699 kg, which is less than 125.
Sav [2.2K]10 days ago
3 0
To tackle this issue, it's essential to understand the conversion of pounds to kilograms:
1 lb = 0.45 Kg
By applying a straightforward rule of three
1 lb ---> 0.45 Kg
125 lb ---> x
Solving for x yields:
x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Response
 her mass in kilograms is 56.25 Kg.
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A sculptor has asked you to help electroplate gold onto a brass statue. You know that the charge carriers in the ionic solution
Maru [2355]

Answer:

Explanation:

Amount of gold deposited = 0.5 g

Gold's molar mass = 197 g/mol

Time duration, t = 6 hours

= 6 × 3600

= 12600 s

Calculation of moles: mass/molar mass

= 0.5/197

= 0.00254 mole

Assuming

Au --> Au+ + e-

Faraday's constant = 9.65 x 10^4 C mol-1

Charge, Q = 96500 × 0.00254

= 244.924 C

Relation: Q = I × t

Thus, I = 244.924/12600

= 0.011 A

= 11.34 mA.

6 0
8 days ago
Which statement is always false for athletes participating in team sports?
Softa [2029]
Which statement can never be true for athletes in team sports? The statement that is always false among the listed options for team sports athletes is choice C) Conflict resolution indicates a lack of sportsmanship. The other statements are valid in the context of team sports.
3 0
5 days ago
The iron ball shown is being swung in a vertical circle at the end of a 0.7-m string. how slowly can the ball go through its top
Keith_Richards [2256]
<span>A centripetal force maintains an object's circular motion. When the ball is at the highest point, we can assume that the ball's speed v is such that the weight of the ball matches the required centripetal force to keep it moving in a circle. Hence, the string will not become slack. centripetal force = weight of the ball m v^2 / r = m g v^2 / r = g v^2 = g r v = sqrt { g r } v = sqrt { (9.80~m/s^2) (0.7 m) } v = 2.62 m/s Thus, the minimum speed for the ball at the top position is 2.62 m/s.</span>
6 0
26 days ago
A proton moves along the x-axis with vx=1.0×107m/s. As it passes the origin, what are the strength and direction of the magnetic
inna [2205]

Answer:

At this position, the magnetic field equals ZERO

Explanation:

The magnetic field produced by a moving charge is described as

B = \frac{\mu_0 qv sin\theta}{4\pi r^2}

Here, we determine the direction of the magnetic field using

\hat B = \hat v \times \hat r

Thus, we find

\hat B = \hat i \times (\hat i + 0\hat j + 0\hat k)

Leading to a magnetic field of ZERO

Consequently, when the charge moves in the same line as the given position vector, the magnetic field will be nonexistent

3 0
10 days ago
The crossbar of a goal post on a professional American football field sits at a height of 3.05 meters (10 feet) above the field.
Sav [2226]

Answer:

A. Yes, the ball clears the crossbar by 2.83 meters

Explanation:

This situation pertains to projectile motion.

The horizontal velocity component of the ball is calculated as 26 cos 35 = 21.3 m/s

The vertical velocity component is 26 sin 35 = 14.9 m/s

The time taken to travel the horizontal distance to the goalpost, which is 54.9 m, is:

= distance / horizontal speed

= 54.9 / 21.3

= 2.577 seconds.

The vertical distance achieved during this time is:

h = ut - 1/2 gt², where u is the initial vertical velocity, and t = 2.577 seconds.

h = 14.9 x 2.577 - 0.5 x 9.8 x (2.577)²

= 38.39 - 32.54

= 5.85 m

Thus, the ball surpasses the crossbar by 5.85 - 3.05 = 2.8 m

5 0
14 days ago
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