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7 days ago

How many electrons does it take to make 80 μc (microcoulombs) of charge?

1 answer:

6 0

The charge for a single electron is 1.602*10^ -19 C

80 µC can be expressed as 8*10^ - 5 C

This is basic arithmetic

Total Charge divided by the charge of one electron = Number of electrons

(8*10^ -5 C / 1.602*10^ -19 C) equals 4.99 * 10^14 electrons.

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A solid metal sphere of diameter D is spinning in a gravity-free region of space with an angular velocity of ωi. The sphere is s

ValentinkaMS [1144]

Answer:

0.6

Explanation:

The formula for the volume of a sphere is $\frac{4}{3} \pi (\frac{D}{2})^3$

Thus $\pi * r^2 * (\frac{D}{2} ) = \frac{4}{3} \pi (\frac{D}{2})^3$

The radius of the disk is $1.15(\frac{ D}{2} )$

Applying angular momentum conservation;

The $M_i$ of the sphere = $\frac{2}{5} m \frac{D}{2}^2$

$M_i$ of the disk = $m*\frac{ \frac{1.15*D}{2}^2 }{2}$

$\frac{wd}{ws} = \frac{\frac{2}{5}m * \frac{D}{2}^2}{ m * \frac{(\frac{`.`5*D}{2})^2 }{2} }$

= 0.6

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4 days ago

A small block of mass 200 g starts at rest at A, slides to B where its speed is vB=8.0m/s,vB=8.0m/s, then slides along the horiz

serg [1189]

Answer

Data provided:

mass of the block = 200 g = 0.2 Kg

Velocity at A = 0 m/s

Velocity at B = 8 m/s

distance of slide = 10 m

height of the block = 4 m

calculation for the block's potential energy

P = m g h

P = 0.2 x 9.8 x 4

P = 7.84 J

kinetic energy calculated as

$KE = \dfrac{1}{2}mv^2$

$KE = \dfrac{1}{2}\times 0.2 \times 7.84^2$

$KE =6.14 J$

Work done = P - KE

work = 7.84 - 6.14

work = 1.7 J

b) using the formula v² = u² + 2 a s

0 = 8² - 2 x a x 10

a = 3.2 m/s²

ma - μ mg = 0

$\mu = \dfrac{a}{g}$

$\mu = \dfrac{3.2}{9.8}$

$\mu = 0.327$

7 0

8 days ago

A rocket takes off vertically from the launch pad with no initial velocity but a constant upward acceleration of 2.25 m/s^2. At

kicyunya [1011]

Answer:

A) 328 m

B) 80.22 m/s

C) 8.18 sec

Explanation:

The rocket's initial acceleration is 2.25 m/s²

Time until engine failure is 15.4 s

Initial velocity u during takeoff = 0 m/s

Distance covered while the engine is functional =?

We apply Newton's laws for this calculation

S = ut + $\frac{1}{2}$ a $t^{2}$

Here, S represents the distance traveled under the rocket's thrust

S = (0 x 15.4) + $\frac{1}{2}$ (2.25 x $15.4^{2}$ )

S = 0 + 266.81 m = 266.81 m

Before the engine fails, the final velocity can be found using:

v = u + at

v = 0 + (2.25 x 15.4) = 34.65 m/s

Once the engine fails, the rocket decelerates under gravitational pull at g = -9.81 m/s² (acting downwards)

The upward initial velocity when freefall begins is v = 34.65 m/s

The final velocity is reached at peak height, where the rocket halts, therefore:

u = 0 m/s

The distance covered during this freefall will be s =?

Utilizing the equation

$v^{2}$ = $u^{2}$ + 2gs

$0^{2}$ = $34.65^{2}$ + 2(-9.81 x s)

0 = 1200.6 - 19.62s

-1200.6 = -19.62s

s = -1200.6/-19.62 = 61.19 m

Thus,

Maximum Height = 266.81 m + 61.19 m = 328 m

At maximum height, the rocket’s initial upward velocity drops to 0 m/s (the rocket completely stops)

The descent occurs freely under g = 9.81 m/s² (acting downwards)

The distance covered during the fall will be 328 m

Final velocity v just prior to impact =?

Applying $v^{2}$ = $u^{2}$ + 2gs

$v^{2}$ = $0^{2}$ + 2(9.81 x 328)

$v^{2}$ = 0 + 6435.36

v = $\sqrt{6435.36}$ = 80.22 m/s

The time taken before reaching the pad is found as follows

v = u + gt

80.22 = 0 + 9.81t

t = 80.22/9.81 = 8.18 sec

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5 days ago

An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the

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Answer:

Please include the diagrams and repost them.

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22 hours ago

Frank wrote several statements to summarize the relationship between the first and second laws of thermodynamics. 1 - Thermal en

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According to the second law, heat, often called thermal energy, cannot be entirely turned into work.
The second statement is closely tied to this law.
We can conclude that some energy dissipates while some is used for work.

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10 days ago

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