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Dafna1
12 days ago
10

A slot machine has 3 dials. Each dial has 30 positions, one of which is "Jackpot". To win the jackpot, all three dials must be i

n the "Jackpot" position. Assuming each play spins the dials and stops each independently and randomly, what are the odds of one play winning the jackpot?
1/30 = 0.03 or 3%


3/(30+30+30) = 3/90 = 0.33 or 33%


3/(30×30×30) = 3/27000 = 0.0001 or 0.01%


1/(30×30×30) = 1/27000 = 0.00003 or 0.003%
Mathematics
2 answers:
zzz [4K]12 days ago
5 0

Answer:

We have three dials on the slot machine, and every dial features 30 different positions.

The likelihood of landing on a specific number on each dial is

30

1

​

Considering the dials operate independently, the chance of hitting the same number across all dials becomes:

P (landing on jackpot) =

30

1

​

 

30

1

​

 

30

1

​

   =    

27000

1

​

   = 0.003%, thus option D is correct.

Step-by-step explanation:

Zina [3.9K]12 days ago
3 0

Answer:

3/(30×30×30) = 3/27000 = 0.0001 or 0.01%

Step-by-step explanation:

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