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IceJOKER
2 months ago
5

If x=3.123, then int(x) will give ?

Computers and Technology
1 answer:
8_murik_8 [964]2 months ago
5 0

Answer:

3

Explanation:

int(x)=3

int(x) rounds down to the nearest integer

For instance,

in the case of int(3.99), the result remains 3

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Natasha_Volkova [1026]
I believe the correct answer is formats
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1 month ago
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In cell F15, insert a function that will automatically display the word Discontinue if the value in cell D15 is less than 1500,
ivann1987 [1066]

Answer:

=IF(D15<1500, "Discontinue", "No Change")

Explanation:

In an Excel environment, you should navigate to cell F15 and apply the IF function. The structure of the IF function is

IF(<condition>, <value if true>, <value if false>)

Your condition is placed before the first comma, which is D15 < 1500.

The second segment, located before the second comma, is the text to display when D15 is below 1500, which is "Discontinue".

Finally, the last part should show text if D15 is 1500 or higher, which is "No Change".

The complete formula can be expressed as =IF(D15<1500, "Discontinue", "No Change")

3 0
2 months ago
#Write a function called "angry_file_finder" that accepts a #filename as a parameter. The function should open the file, #read i
ivann1987 [1066]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

7 0
1 month ago
A large organization is struggling to close the gaps in skill levels that exist between its employees and those from competing c
ivann1987 [1066]

Answer:

C.) by enabling employees to train and enhance skills for more advanced work

Explanation:

Hope this provides assistance!

3 0
1 month ago
CHALLENGE ACTIVITY 2.1.2: Assigning a sum. Write a statement that assigns total_coins with the sum of nickel_count and dime_coun
Harlamova29_29 [1022]

Answer:

In Python:

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Explanation:

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Cheers.

8 0
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