Your school wants to take out an ad in the paper congratulating the basketball team on a successful season, as shown to the rig

Question

14 days ago

15

ht. The area of the photo will be half the area of the entire ad. What is the value of x?

1 answer:

AnnZ [12.3K] · Answer 1 · 2026-04-02T15:16:13+03:00

Answer:

1.4in

Step-by-step explanation:

Length of Photo = 4in

Width of Photo = 3in

Unknown:

Value of X =?

Solution:

Following these steps:

Area of a rectangle = l x w

Considering the photo is rectangular; area of photo:

Area of photo = 4in x 3in = 12in²

For the advertisement's area;

Length of ad = 4 + x

Width of ad = 3 + x

Based on the relation that

the area of the photo = $\frac{1}{2}$ area of ad

12in² = $\frac{1}{2}$ area of ad

Area of ad = 24in²

Advertising Area:

(4 + x) (3 + x) = 24

12 + 4x + 3x + x² = 24

12 + 7x + x² = 24

x² + 7x = 24 - 12

x² + 7x = 12

x² + 7x - 12 = 0

Using the quadratic formula where

a = 1, b = 7 and c = -12

x = $\frac{-b (+/-) \sqrt{b^{2} } - 4ac}{2a}$

x = $\frac{-7 + \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}$ or $\frac{-7 - \sqrt[]{-7^{2} - 4x1x-12 } }{2x1}$

x = 1.4 or -8.4

therefore the answer is 1.4in

x is 1.4in

Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig