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vlabodo
19 days ago
6

A random sample of size 15 taken from a normally distributed population revealed a sample mean of 75 and a sample variance of 25

. The upper limit of a 95% confidence interval for the population mean would equal:
Mathematics
1 answer:
PIT_PIT [12.4K]19 days ago
4 0

Answer:

77.53

Step-by-step explanation:

Sample size (n) = 15

Sample mean (μ) = 75

Sample variance (V) = 25

Sample standard deviation (σ) = 5

For a 95% confidence interval, the z-score equals 1.960

The upper limit of the confidence interval is established as:

UL=\mu+z\frac{\sigma}{\sqrt{n}}\\UL=75+1.960\frac{5}{\sqrt{15}} \\UL = 77.53

Consequently, the upper limit for the 95% confidence interval is 77.53.

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The solution is found in the image attached below.
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Answer:

The correct option is:

On the coordinate plane, there is a parabola that opens upwards, passing through the points (2, 10), having its vertex at (5, 1), and intersecting (8, 10).

Step-by-step explanation:

Initially, we must understand the translation rules

1) {f(x) + a} signifies f(x) moved up by (a) units

2) {f(x) – a} means f(x) moved down by (a) units

3) {f(x + a)} represents f(x) moved left by (a) units.

4) {f(x – a)} indicates f(x) moved right by (a) units.

Given information:

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By comparing the transformation from f(x) to g(x) with the translation rules

It can be concluded that g(x) represents f(x) through a translation of 5 units to the right and 1 unit upwards (rules 1 and 4)

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Answer:

4

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