2,3-Dimethylbutane reacts with bromine in the presence of light to give a monobrominated product. Further reaction gives a good

<span>To determine the specific heat of a solid sample, I’d begin by measuring the mass of the solid. Then, I would prepare a sufficient quantity of water at room temperature to fully submerge the solid. This water would go in an insulated container. I'd then heat the solid to a known temperature. Next, I’d record both the temperature of the solid and the water. After that, I'd submerge the heated sample in the water, allowing them to reach thermal equilibrium. I would then note this final equilibrium temperature. The temperature difference between the heated sample and the equilibrium state indicates the change in temperature of the solid. Given the known mass, initial temperature of the water, and the equilibrium temperature, I can calculate the energy transferred from the solid to the water. With the mass of the sample, the change in temperature of the solid, and the transferred energy, I have enough information to find the specific heat of the solid sample</span>

Answer:

The alteration in the state of matter occurs when sufficient thermal energy is either added to or taken away from an object.

Janice's teacher recommended using temperature to differentiate between the alcohol and water mixture. The relevant property illustrated through this experiment is D. boiling. The boiling point is the temperature at which a liquid transitions into vapor. Water boils at 100°C under atmospheric pressure, while most alcohols have lower boiling points. Recognizing the significant boiling temperature disparity between the two substances was essential for their separation.

Molarity is calculated using moles divided by the volume in liters. Convert 200 mL to 0.2 L, then divide 2 moles by 0.2 L.

Answer:

C₂H₅O₂

Explanation:

From the information provided in the question, we have the following details:

Mass of compound = 0.25 g

Mass of CO₂ = 0.3664 g

Mass of H₂O = 0.15 g

Empirical formula =?

Now, let’s calculate the masses of carbon, hydrogen, and oxygen within the compound as follows:

For Carbon (C):

Mass of CO₂ = 0.3664 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mass of C = 12/44 × 0.3664

Mass of C = 0.1

For Hydrogen (H):

Mass of H₂O = 0.15 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H = 2/18 × 0.15

Mass of H = 0.02 g

For Oxygen (O):

Mass of C = 0.1 g

Mass of H = 0.02 g

Mass of compound = 0.25 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.25 – (0.1 + 0.02)

Mass of O = 0.25 –0.12

Mass of O = 0.13 g

In conclusion, we will now find the empirical formula for the compound:

C = 0.1

H = 0.02

O = 0.13

Next, we divide by their respective molar mass:

C = 0.1 / 12 = 0.0083

H = 0.02 / 1 = 0.02

O = 0.13 / 16 = 0.0081

Then we divide by the smallest value:

C = 0.0083 / 0.0081 = 1

H = 0.02 / 0.0081 = 2.47

O = 0.008 / 0.008 = 1

Finally, we multiply by 2 to present in whole numbers:

C = 1 × 2 = 2

H = 2.47 × 2 = 5

O = 1 × 2 = 2

Therefore, the empirical formula for the compound is C₂H₅O₂