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Alenkinab
2 months ago
10

Describe how you could determine the specific heat of a sample of a solid substance. You may assume that the substance does not

react with water. In your answer, make sure to include a description of what equipment you would use and how you would interpret the data you collected.
Chemistry
2 answers:
eduard [2.7K]2 months ago
8 0

Response:

To find the specific heat, I would utilize calorimetry to measure the sample's mass. Heating the sample to a specific temperature, I'd then introduce it into a coffee-cup calorimeter containing a known mass of water at a specific initial temperature. After allowing the temperatures to equilibrate, I would determine the change in temperature. This temperature change of the water reflects the energy absorbed. Using the energy lost by the solid sample, its mass, and the temperature change, I can calculate the specific heat.

Explanation:

castortr0y [3K]2 months ago
6 0
<span>To determine the specific heat of a solid sample, I’d begin by measuring the mass of the solid. Then, I would prepare a sufficient quantity of water at room temperature to fully submerge the solid. This water would go in an insulated container. I'd then heat the solid to a known temperature. Next, I’d record both the temperature of the solid and the water. After that, I'd submerge the heated sample in the water, allowing them to reach thermal equilibrium. I would then note this final equilibrium temperature. The temperature difference between the heated sample and the equilibrium state indicates the change in temperature of the solid. Given the known mass, initial temperature of the water, and the equilibrium temperature, I can calculate the energy transferred from the solid to the water. With the mass of the sample, the change in temperature of the solid, and the transferred energy, I have enough information to find the specific heat of the solid sample</span>
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How many milliliters of 0.200 M NH4OH are needed to react with 12.0 mL of 0.550 M FeCl3?
eduard [2782]

Response:

9.9 ml of 0.200M NH₄OH(aq)

Reasoning:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

What volume in ml of 0.200M NH₄OH(aq) will fully react with 12ml of 0.550M FeCl₃(aq)?

1 x Molarity of NH₄OH x Volume of NH₄OH Solution(L) = 2 x Molarity of FeCl₃ x Volume of FeCl₃ Solution

1(0.200M)(Volume of NH₄OH Soln) = 3(0.550M)(0.012L)

=> Volume of NH₄OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liters = 9.9 milliliters

5 0
3 months ago
NiO is to be reduced to nickel metal in an industrial process by use of the reaction:NiO(s) + CO(g) &lt;-----&gt; Ni(s) + CO2(g)
alisha [2963]

Answer:

The reaction will proceed in the forward direction, resulting in the reduction of NiO to Ni

Explanation:

Step 1: Provided data

Kp = 6.0 * 10²

Pressure of CO = 150 torr

Total pressure remains under 760 torr

Step 2: The balanced reaction equation:

NiO(s) + CO(g) ⇆ Ni(s) + CO2(g)

Step 3: Determine P(CO) and P(CO2)

For this equilibrium, the Kp expression is:

Kp = P(CO2)/P(CO) = 6.0*10^2

Given that NiO and Ni are solids, they do not affect the Kp

⇒ with P(CO) = 150 torr

⇒ P(CO) = 760 - 150 = 610 torr

Step 4: Calculate the reaction quotient

Q = 610/150 = 4.1

Since Q is significantly less than Kp, there are more reactants than products. Some reactants will convert into products, driving the reaction rightward.

Thus, the reaction will proceed forward, leading to the reduction of NiO to Ni.

6 0
3 months ago
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