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jenyasd209
2 days ago
9

Squaring both sides of an equation is irreversible. Is Cubing both sides of an equation reversible? Provide numerical examples t

o help support your answer.
Mathematics
1 answer:
AnnZ [10.9K]2 days ago
4 0
Cubing both sides of an equation is a reversible process. Detailed explanation: Squaring both sides isn't reversible because squaring a negative number produces a positive result, thus making it impossible to retrieve the original negative base, as square roots of negative numbers do not exist within real numbers. In contrast, cubic powers allow for reversibility; the cubic root of a negative number remains negative. For example, if we cube both sides and wish to revert to the original equation, we can do so using the cubic root on each side. Hence, cubing both sides is reversible.
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Exhibit: Department Store.
Inessa [11115]
In detail: Based on the central limit theorem, the distribution appears normal due to the large sample size. The confidence interval is presented in the format: (Sample mean - margin of error, sample mean + margin of error). The sample mean, denoted as x, serves as the point estimate for the population mean. The confidence interval is computed as: mean ± z × σ/√n, where σ represents the population standard deviation. The formula transforms into confidence interval = x ± z × σ/√n, with specific values: x = $75, σ = $24. To find the z score, we subtract the confidence level from 100% which gives α as 1 - 0.96 = 0.04; halving this results in α/2 = 0.02, signifying the tail areas. To ensure we account for the center area, we have 1 - 0.02 = 0.98, corresponding to a z score of 2.05 for the 96% confidence level. The confidence interval becomes 75 ± 2.05 × 24/√64 = 75 ± 2.05 × 3 = 75 ± 6.15. The lower limit is 75 - 6.15 = 68.85, while the upper limit stands at 75 + 6.15 = 81.15. For n = 400, with x = $75 and σ = $24, the z score remains 2.05, resulting in the confidence interval calculated as 75 ± 2.05 × 24/√400 = 75 ± 2.05 × 1.2 = 75 ± 2.46. Subsequently, the lower bound becomes 75 - 2.46 = 72.54, and the upper limit adds up to 75 + 2.46 = 77.46. Lastly, when n = 400, x = $200, and σ = $80, the z score tied to a 94% confidence level is 1.88. Thus, the confidence interval is expressed as 200 ± 1.88 × 80/√400 = 200 ± 1.88 × 4 = 200 ± 7.52, giving us a margin of error of 7.52.
7 0
18 days ago
Rapunzel cut 2/3 of of her hair. She donated 7/8 of what she cut off to a wig shop.
Zina [11157]
2/3 of 7/8
2/3×7/8=7/12
8 0
5 days ago
Read 2 more answers
The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a
Leona [11148]

Answer:

The range of cheerleaders' heights lies within the interval [58, 74)

It includes all real numbers from 58 inches and above, but below 74 inches.

Step-by-step explanation:

we have

260 \leq 4h+28

Separate the combined inequality into two distinct inequalities

260 \leq 4h+28 -----> inequality A

4h+28 -----> inequality B

Solve inequality A

260 \leq 4h+28

Subtract 28 from both sides

232 \leq 4h

Split by 4 on both sides

58 \leq h

Reformulate

h \geq 58\ in

Address inequality B

4h+28

Subtract 28 from both sides

4h

Split by 4 on both sides

h

consequently

The height range of the cheerleaders is the interval [58, 74)

It consists of every real number starting from 58 inches and less than 74 inches

3 0
1 month ago
Find the value of y if EF = EG.​
AnnZ [10913]

Answer:

55°

Step-by-step explanation:

The problem does not have a suitable diagram. Please check the attachment for the diagram.

Observing the diagram, it is evident that the triangle is isosceles, as it has two sides that are congruent (i.e., the same length). Since these sides are identical, the base angles are consequently also equal.

From the diagram, <EFG = <EGF

Since  <EFG  = 55°, it follows that  <EGF = y = 55°

Thus, the value of y is established as 55°

5 0
10 days ago
Tricia is going to write Patterns A , B , and C using the rule add 15. The first number in each pattern is shown below . Use the
Inessa [11115]

Response:

The number 40 can be found in Pattern B. Additionally, following the rule, each sequence will expand.

Detailed breakdown:

Let’s build each sequence. Recall that the guideline is to "add 15" to generate each sequence starting from the provided initial number.

Pattern A.

5+20+35+50+65+80+95+110+125+140+155+170+185+200+215+...

Pattern B.

10+25+40+55+70+85+100+115+130+145+160+175+190+205+...

Pattern C.

15+30+45+60+75+90+115+130+145+160+175+190+205+...

You can see that the number 40 appears in Pattern B. Moreover, per the rule, each pattern will show an increase.

8 0
27 days ago
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