Write the equation of the line that is parallel to the line y=−14x−3 through the point (4,4). A. y=x+5 B. y=−14x+5 C. y=5x+1 D.

Answer:

The answer to this question is C: (72,24).

Step-by-step explanation:

According to the information provided:

The price of one cap is $5

The price of one t-shirt is $10

Let x represent the number of caps sold

Let y represent the number of t-shirts sold

The drama club aims to raise at least $500 for their trip.

Inequality: 5x + 10y ≥ 500 (The greater than or equal to symbol indicates the drama club needs at least $500 for the journey.Next, we need to ascertain the number of caps and t-shirts sold.

- We can eliminate

of the options which are

because we understand that multiplying a positive by a negative yields a negative, which is unacceptable. (Thus, Options A and D are not valid.)Now we will substitute x and y into our inequality equation (5x + 10y ≥ 500)B) x = 65 caps, y = 17.5 t-shirts ------> 5(65) + 10(17.5) = 500 results in $500

YOU MAY THINK THIS IS THE ANSWER, BUT! if you look closely at variable y, it indicates they sold 17.5 t-shirts; however, consider how can you sell 17.5 t-shirts?

Thus, this option is also invalid!

$600

which exceeds the required $500 that they needed. Therefore, the correct choice for this question is C, indicating they sold 72 caps and 24 t-shirts, accumulating $600.

Answer:

a) Null hypothesis:

Alternative hypothesis:

b)

Given that the p-value is lower than the significance threshold in this situation, we have sufficient grounds to reject the null hypothesis.

c)

In this case, since the p-value exceeds the significance threshold, we have adequate evidence to FAIL to reject the null hypothesis.

d)

Here again, with the p-value being less than the significance level, we can reject the null hypothesis.

Step-by-step explanation:

1) Provided data and references

represents the average of the samples

denotes the standard deviation of the samples

indicates the number of samples

is the value we are examining

defines the significance level for the test.

t represents the specific statistic of interest

indicates the p-value relevant to the test (the variable of concern)

Define the null and alternative hypotheses.

To assess if the true mean is at least 10 hours, we must set up a hypothesis:

Part a

Null hypothesis:

Alternative hypothesis:

If we consider the sample size being less than 30 and the population deviation unknown, it’s more appropriate to use a t-test to compare the actual mean with the reference value, calculated as:

(1)

Part b

In this scenario t=-2.3,

Initially, we need to calculate the degrees of freedom

Since this is a left-tailed test, the p-value is determined by:

In this instance, with the p-value being less than the significance level, we have sufficient evidence to reject the null hypothesis.

Part c

For this situation t=-1.8,

We need to find the degrees of freedom

For the left-tailed test, the p-value is given by:

In this case, since the p-value is above the significance level, we have enough grounds to FAIL to reject the null hypothesis.

Part d

For this case t=-3.6,

Firstly, we find the degrees of freedom

Since we are conducting a left-tailed test, the p-value is calculated as:

Here, with the p-value being lower than the significance threshold, we can reject the null hypothesis.