Response with clarification:
Let p denote the proportion of adults in the town who have encountered this flu strain.
According to the provided information
∵ 
this is a two-tailed test.
Test statistic:
, where p= denotes the population proportion
= signifies the sample proportion
n= represents the sample size
Setting n= 6 and 
and p=0.08
P-value for the two-tailed test:[2P(Z>|z|)
=2P(Z>|-0.415|)
=2P(Z>0.415) = 2[1-P(Z≤0.415)] [∵ P(Z>z)=1-P(Z≤z)]
=2(1-0.6609) [from the z-table]
=0.6782
Decision: Because the p-value(0.6782) exceeds the significance level of 0.01, we do not reject the null hypothesis.
This leads us to conclude that there is insufficient evidence to back the assertion that the percentage of all adults in this town exposed to this flu strain deviates from the national average of 8%.
Response:
The measure of mHLK is "(204)°".
Step-by-step breakdown:
Given values include:
mJI = (3x+2)°
mHLK = (15x-36)°
and,
m∠HML = (8x-1)°
then,
What is mHLK?
Now,
Utilizing the chord-chord angle formula, we find
Inserting the known values into the equation gives us
⇒ 
By carrying out cross-multiplication, we arrive at
⇒ 
⇒ 
By subtracting "18x" from both sides, we obtain
⇒ 
⇒ 
Upon adding "2" to both sides, we end up with
⇒ 
⇒ 
⇒ 
⇒ 
By substituting the value of "x" into mHLK = (15x-36)°, we calculate
⇒ (15x-36)° = (15×16-36)°
⇒ = (240-36)°
⇒ = (204)°
Thus, mHLK = (204)°
Response:
The fence's length is expressed as 6.28x - 150 cm.
Detailed Breakdown:
Assuming the circular pool has a radius (r) of x cm.
As the pool is circular, its circumference represents the length of the fence. Additionally, subtracting the 150 cm for the gate gives us the actual length of the fence.
Length of fence = Circumference of pool – gate's width.
Length of fence = 2 π r – 150
Length of fence = 2 × 3.14 × x – 150
Therefore, the fence length is 6.28x – 150 cm.
