Response:The ethanol percentage is 0.1093%
Explanation:
As given:
t = time = 10 s
I = current = 320 mA
F = Faraday's constant = 96485.3365 C mol⁻¹
n = number of electrons transferred = 4
Molecular weight of ethanol is 46 g/mol
Question: What is the percent (by volume) of ethanol in the driver's breath, %E =?
First, calculate the ethanol mass:
The moles of ethanol:
Applying the ideal gas law formula:
Here:
T = 26°C = 299 K
P = 1 atm
Substituting in the values:
The percentage of ethanol:
%
The solution to your inquiry yields P = 17.73 atm. Explanation: The volume V is 250 ml, equivalent to 0.25 liters (L), with a mass of 3.4 g and a temperature of 45°C, which converts to 318°K. We utilize the ideal gas law PV = nRT for the calculations.
They overcomplicated things with lots of words. Your initial equation deals with the revenue. I’ll denote tacos as x and burritos as y.
The first equation would be 3x + 7.25y = 595, given that you already have the prices but need the quantities. The second equation will reflect that double the burritos were sold compared to tacos, expressed as y = x + 2.
Hope this clarifies things. If you need further explanation, I can elaborate more.
Answer: The process of heating a crucible to eliminate moisture from a hydrate.
Explanation:
The available choices are:
a. Heating a solvent to aid in the dissolution of a solute.
b. Heating a solid in isolation to remove moisture.
c. Bringing water to a boil for use in a water bath.
d. Heating a crucible to eliminate moisture from a hydrate.
Possible actions that can be done on a hot plate include:
a. Heating a solvent to assist a solute in dissolving.
b. Heating a solid in isolation to dry it.
c. Heating water to boiling for a water bath.
However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.
Consequently, the correct procedure is heating a crucible to remove water from a hydrate.
CxHy + (x+0.25)O₂ → xCO₂ + 0.5yH₂O
m(CO₂)/{xM(CO₂)}=m(H₂O)/{0.5yM(H₂O)}
0.2845/{44.01x}=0.1451/{9.01y}
x/y=0.4=2:5
The empirical formula is C₂H₅.
