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KATRIN_1
1 month ago
8

A 250 ml flask contains 3.4 g of neon gas at 45°c. Calculate the pressure of the neon gas inside the flask.

Chemistry
1 answer:
eduard [2.7K]1 month ago
7 0
The solution to your inquiry yields P = 17.73 atm. Explanation: The volume V is 250 ml, equivalent to 0.25 liters (L), with a mass of 3.4 g and a temperature of 45°C, which converts to 318°K. We utilize the ideal gas law PV = nRT for the calculations.
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Suppose you have a bucket of sand containing 5.5 billion grains of sand ( 5.5×109 grains). Most of the grains of sand are white,
alisha [2963]

Explanation:

5.5 billion grains of sand (5.5×10^9 grains)

Assuming the amount of brown sand is 6.0%, how many brown grains are found in the bucket?

Grains of brown sand = Percentage of brown sand * Total sand in the bucket

Calculated brown grains = 0.06 * 5.5×10^9 = 0.33 x 10^9 = 3.3 x 10^8 grains

If the concentration of brown sand is 6.0 ppm, what is the number of brown grains in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppm = 6 / 1,000,000 = 0.000006

Calculated brown grains = 0.000006 * 5.5×10^9 = 3.3 x 10^4 grains

If the concentration of brown sand is 6.0 ppb, how many brown grains exist in the bucket?

Grains of brown sand = Concentration of brown sand * Total sand in the bucket

6 ppb = 6 / 1,000,000,000 = 0.000000006

Calculated brown grains = 0.000000006 * 5.5×10^9 = 3.3 x 10^1 = 33 grains

5 0
2 months ago
When a heavy football player and a light one run into each other, which player hits the other with
Anarel [2989]

A heavier player collides with a lighter player using greater force.

The lighter player sustains more injuries following the impact.

Explanation:

A heavier player impacts a lighter player with greater intensity, resulting in more pronounced injuries to the lighter player post-collision.

Force is defined as mass multiplied by the acceleration of an object;

    Force = mass x acceleration

We observe that as mass and acceleration increase, the force exerted rises accordingly.

Clearly, the heavier player's mass surpasses that of the lighter player, leading to a greater force exerted upon collision.

Moreover, the lighter player is likely to be injured more severely after the clash. The momentum generated by the heavier player during the impact is considerably significant. Once they collide, the lighter player will certainly alter their speed and trajectory.

Learn more:

Momentum

5 0
3 months ago
Acrylonitrile () is the starting material for many synthetic carpets and fabrics. It is produced by the following reaction. If 1
alisha [2963]

2C3H6 (g) + 2NH3 (g) + 3O2 (G) -> 2C3H3N (g) + 6H2O (g)

To begin, this isn't really a chemistry forum, but anyway.

This represents a limiting reagent scenario.

Set it up as a Dimensional Analysis issue.

Begin with your desired outcome.

Your goal is to find the mass of acrylonitrile (C3H3N)

so you should initiate with that (I'll abbreviate Acrylonitrile as ACL for convenience)

(g) = (53 g of ACL/1mol ACL) (2 mols ACL/2 mol C3H6)/ (1mol C3H6/42 grams) (15.0 grams)

If you calculate that, you will find that 15 grams of C3H6 yields 18.9 grams of acrylonitrile produced.

Utilize the same approach for the remaining two reactants.

So, I figured it out, and for

oxygen, I calculated 11.04 grams

and for ammonia, I calculated 15.29 grams

This means that the maximum possible production is 11.04 grams, since to create any additional amount, more O2 would be necessary, but with only 10 grams available, that's the upper limit for this reaction.

The other two reactants are in excess.

Please rate as brainliest!

3 0
2 months ago
Calculate the change in internal energy of the following system: a 100.0-g bar of gold is heated from 25 ∘C to 50 ∘C during whic
castortr0y [3046]
According to the Law, the variation in internal energy (U) of the system is equal to the total of the heat added to the system (q) plus the work performed ON the system (W)
<span>ΔU = q + W </span>

<span>In response to the first question, 0.653 kJ of heat energy is extracted from the system (balloon) while 386 J of work is applied to the balloon, leading to </span>
<span>ΔU = -653J + 386J </span>
<span>=-267J </span>
<span>Thus, the internal energy reduces by 267 J </span>

<span>For the second question, 322 J of heat is supplied to the system (gold bar) while no work is undertaken on the gold bar, marking this as an isochoric/isovolumetric process, thus </span>
<span>ΔU = 322J + 0 </span>
<span>=322J </span>
<span>Hence, internal energy rises by 322 J</span>
8 0
1 month ago
Read 2 more answers
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