<span>Response:
A 1.00 L solution that includes 3.00x10^-4 M Cu(NO3)2 and 2.40x10^-3 M ethylenediamine (en).
Contains
0.000300 moles of Cu(NO3)2 and 0.00240 moles of ethylenediamine.
Using the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts with double that amount of en = 0.000600 mol of en.
Thus, 0.00240 moles of ethylenediamine - 0.000600 mol of en reacted leaves 0.00180 mol en unreacted.
According to the formula Cu(en)2^2+
0.000300 moles of Cu(NO3)2 reacts to yield an equivalent of 0.000300 moles of Cu(en)2^2+
The formation constant Kf for Cu(en)2^2+ is 1x10^20.
Therefore,
1 Cu+2 and 2 en --> Cu(en)2^2+
Kf = [Cu(en)2^2+] / [Cu+2] [en]^2
1x10^20 = [0.000300] / [Cu+2] [0.00180 ]^2
Solving for [Cu+2] gives [Cu+2] = [0.000300] / (1x10^20) (3.24 e-6)
Thus, Cu+2 = 9.26 e-19 Molar.
Since Kf only has 1 significant figure, round that to 9 X 10^-19 Molar Cu+2.</span>
<span>To calculate the area of a sheet of paper in square centimeters, one must first transform the paper dimensions into centimeters. This can be done by multiplying 8.5 by 2.54 and 6.5 by 2.54. The resultant paper dimensions are 21.59cm by 16.51cm. The area is then determined by multiplying these dimensions, yielding an area of 356.4509cm2</span>
No, two atoms that have identical mass numbers can never be considered isotopes of one another. This is due to the fact that for atoms to qualify as isotopes, they must consist of the same number of protons while differing in the number of neutrons. If two atoms share the same mass number, their proton count must also be identical, which implies these atoms cannot be isotopes of each other.
Answer:
Ir(NO2)3
Explanation:
The molar mass is 330.2335, in case that's also required.
The result is: 3.36 micrograms of iron in<span> Greg's blood sample.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Using proportions: m(Fe): 8 mL = 42 mcg: 100 mL.
Thus, 100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3.36 mcg.
