Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of co2 and 0.1451 g of h2o. wha

Answer:

The mass percentage of GaBr₃ in the solid mixture is 30.2 %.

Explanation:

GaBr₃(aq) + 3 AgNO₃(aq) ⟶ 3 AgBr(s) + Ga(NO₃)₃(aq)

To find the molar mass, we have: MW GaBr₃ = 309.4 g/mol and MW AgBr = 187.8 g/mol.

Using these values, we note that 187.8 g of AgBr corresponds to 1 mol.

If 0.368 g of AgBr yields x moles, we calculate x to be 2.0 x 10⁻³ mol AgBr.

Based on the stoichiometry, 1 mol of GaBr₃ produces 3 mol of AgBr, giving us:

y ___________ 2.0 x 10⁻³ mol AgBr

Thus, y equals 6.7 x 10⁻⁴ mol GaBr₃.

Additionally, 1 mol of GaBr₃ has a mass of 309.4 g.

Consequently, 6.7 x 10⁻⁴ mol of GaBr₃ corresponds to w grams of GaBr₃, yielding w = 0.206 g GaBr₃.

Relating this to the total mass:

0.6813 g _____ 100%

0.206 g _____ z

Therefore, z is calculated as 30.2 %.

The mass of magnesium consumed amounts to 21.42g. Explanation: As per the balanced reaction, three moles of magnesium react with one mole of nitrogen, producing one mole of magnesium nitride. Given that the mass of nitrogen involved equals 8.33g, the moles of the reacted nitrogen equal a particular quantity. The required moles of magnesium, therefore, equals three times the moles of nitrogen utilized. Subsequently, the mass of magnesium needed is determined by multiplying the moles by its molar mass.

The answer is.997 atm. 1. Identify the combined gas law equation... (P1V1/T1 = P2V2/T2) 2. Gather our values... P1=.982 atm P2=? (this is what we want to find) V1= 2 L V2= 1.8 L T1= 22 C = 295 K T2= -3 C = 270 K - Note: Always convert to Kelvin. To do this, add 273 to the Celsius value. 3. Rearranging the formula to suit this problem... (P2=P1V1T2/V2T1) 4. Insert our values... P2=.982 atm x 2 L x 270 K / 1.8 L x 295 K 5. Calculate and the result should yield....997 atm - If you require further clarification or assistance, feel free to reach out and I'll be happy to help!

The oxidation state numbercan aid in identifying the unknown element present in both compounds. They denote the number of electrons that are either donated, received, or shared to yield compounds.

Remember the fundamental principles governing oxidation numbers.

1. In a neutral compound, the total of all oxidation numbers is zero.
2. Chlorine, bromine, and iodine typically exhibit an oxidation number of -1(unless paired with fluorine and oxygen)

Assume the oxidation state for element Mis designated as x.
Referring to rule 2, chlorine possesses an oxidation state of -1.

Now, for the compound MCl₂ (which is neutral), the equation can be formulated as
x + (2 * -1)= 0 ⇒ x₁= +2

For MCl₃, the corresponding equation is
x + (3 * -1)=  0 ⇒ x₂= +3

This indicates that the elementhas two distinct oxidation statesin its compounds, which are +2and +3.

The identified element is iron (Fe), as it shows +2 and +3 oxidation states across these compounds.

Memorizing this is essential. Regrettably, there isn't a simpler method to tackle these oxidation states.

The final answer is iron (Fe).

DNA is the biomolecule in question.