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Anton
2 months ago
9

Raymond spends 1/10 of his vacation budget on a car rental. Write an expression for how much he has to spend on the rest of his

vacation. If he budgets $650 for the vacation, how much will he have left to spend?
Mathematics
2 answers:
PIT_PIT [12.4K]2 months ago
3 0
When he spends 1/10 of his vacation fund on car rental, he is left with 9/10 of his budget for the remaining vacation expenses

9/10(650) = 5850/10 = 585 remaining for vacation
or this method can also be used...

650 - 1/10(650) =
650 - 650/10 = 650 - 65 = 585 available for his vacation.
Leona [12.6K]2 months ago
3 0
Raymond utilized $65 from a total of $650, thus retaining $585.
650/10=65
650-65=585
alternatively (650/10)-65=585
the / indicates division. 
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Calvin deposits $400 in a savings account that accrues 5% interest compounded monthly. after c years, calvin has $658.80. makayl
lawyer [12517]
To calculate this, a specific formula will be necessary. Years = log (total/principal) / [n * log (1 + rate / n)]. Part A) For Calvin: $400 at 5% monthly results in $658.80; Time =? Monthly compounding, n = 12. Thus, Years = log(658.80/400) / [12 * log(1+ (.05/12))]. Subsequently, Years = log( 1.647) / (12 * log(1.0041666667)). Then, Years = 0.21669359917 / 12 * 0.0018058008777. Thus resulting in Years = 0.21669359917 / 0.0216696105. Ultimately, Years ≈ 9.999884362. Part B) For Makayla: $300 at 6% quarterly yields $613.04; Time=? Quarterly compounding, n = 4. Therefore, Years = log(613.04/300) / [4 * log (1 +.06/4)]. This results in Years = log(2.0434666667) / (4 * log(1.015)). Years thus equals 0.31036755784 / (4 * 0.0064660422492), resulting in Years ≈ 11.9999044949. The approximate difference is about 3 years.
3 0
2 months ago
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You provide a dog-walking service, and you report to the owners on the amount of exercise their dogs get on the walks. You walke
babunello [11817]

Answer E is correct, as when rounded to 3 mph and divided by 2, it yields 1.5. Since an hour consists of 60 minutes, halving that gives 30 minutes. However, because you walked a bit slower, it would actually take 5 additional minutes.

7 0
3 months ago
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What is a3 in an arithmetic sequence in which a10=41 and a15=61
zzz [12365]
\bf \begin{array}{llll}
term&value\\
-----&-----\\
a_{10}&41\\
a_{11}&41+d\\
a_{12}&(41+d)+d\\
&41+2d\\
a_{13}&(41+2d)+d\\
&41+3d\\
a_{14}&(41+3d)+d\\
&41+4d\\
a_{15}&(41+4d)+d\\
&41+5d=61
\end{array}
\\\\\\
41+5d=61\implies 5d=20\implies d=\cfrac{20}{5}\implies \boxed{d=4}\\\\
-------------------------------\\\\

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=10\\
a_{10}=41
\end{cases}
\\\\\\
41=a_1+(10-1)4\implies 41=a_1+36\implies \boxed{5=a_1}

therefore

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=4\\
n=3\\
a_{1}=5
\end{cases}
\\\\\\
a_3=a_1+(3-1)4\implies a_3=5+(3-1)4

and you are probably aware of the amount.
8 0
2 months ago
Read 2 more answers
a falling object travels a distance given by the formula d=5t + 16t^2 ft, where t is measured in seconds. how long will it take
zzz [12365]

It is provided that

d=5t+16t^{2}

We need to determine t when d equals 74

Thus, 74=5t+16t^{2} or

16t^{2}+5t-74 = 0

16t^{2}+37t-32t-74 = 0

t(16t + 37) - 2(16t + 37) = 0

(t - 2)(16t + 37) = 0

t - 2 = 0 or 16t + 37 = 0

t cannot be negative.

Thus, t equals 2

Therefore, it will require 2 seconds for the object to cover 74 feet.










8 0
3 months ago
Read 2 more answers
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