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Anton
18 days ago
9

Raymond spends 1/10 of his vacation budget on a car rental. Write an expression for how much he has to spend on the rest of his

vacation. If he budgets $650 for the vacation, how much will he have left to spend?
Mathematics
2 answers:
PIT_PIT [12.4K]18 days ago
3 0
When he spends 1/10 of his vacation fund on car rental, he is left with 9/10 of his budget for the remaining vacation expenses

9/10(650) = 5850/10 = 585 remaining for vacation
or this method can also be used...

650 - 1/10(650) =
650 - 650/10 = 650 - 65 = 585 available for his vacation.
Leona [12.6K]18 days ago
3 0
Raymond utilized $65 from a total of $650, thus retaining $585.
650/10=65
650-65=585
alternatively (650/10)-65=585
the / indicates division. 
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Answer:

The correct response is B, expressed as d=45t.

Step-by-step explanation:

I just completed the problem and arrived at the right solution.

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8 0
1 month ago
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u
PIT_PIT [12445]

Answer with Step-by-step explanation:

We are given Laplace's equation:

u_{xx}+u_{yy}=0

We need to verify if the presented functions satisfy this equation.

A function solves Laplace's equation only if the sum of its second partial derivatives with respect to x and y equals zero.

For the first function:u=e^{-x}cosy-e^{-y}cosx

Compute the first derivative with respect to x:

u_x=-e^{-x}cosy+e^{-y}sinx

Then find the second derivative with respect to x:

u_{xx}=e^{-x}cosy+e^{-y}cosx

Next, derive with respect to y:

u_y=-e^{-x}siny+e^{-y}cosx

Then the second derivative with respect to y:

u_{yy}=-e^{-x}cosy-e^{-y}cosx

Substitute into Laplace's equation:

e^{-x}cosy+e^{-y}cosx-e^{-x}cosy-e^{-y}cosx=0

Therefore, the function satisfies Laplace's equation.

For the second function:u=sinx coshy+cosx sinhy

First partial derivative w.r.t x:

u_x=cosx coshy-sinx sinhy

Second derivative w.r.t x:

u_{xx}=-sin x coshy-cosxsinhy

First derivative w.r.t y:

u_y=sinx sinhy+cosx coshy

Second derivative w.r.t y:

u_{yy}=sinx coshy+cosx sinhy

After substituting, we have:

-sinx coshy-cosxsinhy+sinxcoshy+cosx sinhy=0

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4 0
2 months ago
Katie solves 15 problems in 6 hours. At the same pace how long would it take her to solve 28 problems?
Inessa [12570]

Response:

15:6 = 5:2=28:x

x=11.2, approximately 12 hours.

Step-by-step explanation:

5 0
1 month ago
the product of two numbers is 450. the first number is half the second number. which equation can be used to find x, the greater
AnnZ [12381]
Xy = 450

y = x/2 => x=2y  plugging this into the first equation yields 2y*y=450 => y^2 = 225

y=15 since 15*15=225

x=2y therefore x=2*15 = 30 

x=30
y=15

I hope this is helpful to you 
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