Answer:2688.63 miles
Step-by-step explanation:
Given
The distance from Paris to Los Angeles 
Wind traveling at 100 mph from Los Angeles to Paris
The velocity of the plane through still air is 
Relative velocity of Plane A is 
since Plane A is heading against the wind
Relative velocity of Plane B is 
Plane A departs at noon
Distance covered by Plane A in 1 hour 
The total separation distance between the planes is 
Assuming they meet after t hours
Distance covered by Plane B in that time frame 
Distance traveled by Plane A in t hours is 
The total distance equals 4550 miles
Distance traveled by B is 
thus, they meet at a point 2688.63 miles away from Los Angeles.
65,000. I'm quite certain because a 1 wouldn't be sufficient to shift the 5 higher.
To determine the answer, you need to divide 405 by 50 to discover the weight of a single coin. The calculation should appear like this:
= 8.1
The precise weight is 8.1 grams, but if you are looking for an estimate, the conclusion should be
Approximately 8 grams for a one-dollar coin
To formulate the system, it's necessary to consider the slope of each line along with at least one point from each line. The two lines will connect each plane's location to their destination airport. It's important to note that the airport's coordinates represent the intersection of these two lines, corresponding to the solution of the system. First, the slope of the line from airplane one to the airport is: m = 2; this can be observed by plotting the two points. From airplane 1's location, the rise is 8 units while the run is 4 units to reach the airport, making the slope 8 divided by 4 = 2. We then insert the slope and point (2,4) into the point-slope form: y - 4 = 2(x - 4), which can be rearranged to standard form 2x - y = 0. For airplane two, the slope to the airport is obtained by observing the vertical decrease of 3 and a horizontal increase of 9 as we move from the airport to airplane 2. We then substitute the slope and the point (15,9) into the point-slope form: y - 9 = -1/3(x - 15), which can be rearranged to the standard form: x + 3y = 42. Consequently, the system of equations is: 2x - y = 0 and x + 3y = 42. Multiplying the first equation by 3 produces a system of: 6x - 3y = 0 and x + 3y = 42. Adding these equations results in the equation 7x = 42. Thus, x = 6, and by substituting this value back into 2x - y = 0, we determine y = 12. Thus, we demonstrate that the airport's coordinates do indeed comprise the solution to our system.
To calculate the area, simply multiply 5 by 4, resulting in 20.
