Answer:
The molar mass of the metal in grams per mole is calculated to be 8.87.
Explanation:
Initially, we can consider a sample of the compound weighing 100 g. This results in:
- 52.92% metal: 52.92 g M
- 47.80% oxygen: 47.80 g O
By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=2.9875
The formula for the metal oxide indicates that:
2 M⁺³ + 3 O²⁻ ⇒ M₂O₃
From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass≅ 8.87 g/mol
The molar mass of the metal in grams per mole is 8.87.
The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.
The result is 70.5 km/h. It seems the question is somewhat vague, but you're inquiring about the x-component of the helicopter's velocity. The x and y components can be calculated using sine and cosine ratios. The sine ratio connects the y-component with the overall velocity as follows: sin(angle) = y-component of velocity / velocity. Meanwhile, the cosine ratio relates the x-component to the velocity: cos(angle) = x-component of velocity / velocity. Given that you have both the angle and the velocity, and need to determine the x-component, you should apply the cosine ratio: cos(35°) = x-component / 86.0 km/h => x-component = 86.0 km/h * cos(35°) = 70.5 km/h.
Explanation:
Attached is a document that contains the solution.
An increase in temperature and an increase in pressure can lead to a rise in the frequency of collisions. This can occur in several ways: first, the speed of gas molecules can be enhanced by raising their temperature, which directly affects their kinetic energy, allowing them to collide more often due to increased velocity. Secondly, if the container's size decreases, gas molecules will have less room to navigate and will therefore collide more frequently with the container's walls, increasing pressure, similar to what occurs in a piston-cylinder system.
Response:
To find power, we must first determine the work done by the force.
1) We will use the following equation to calculate work:

The force is provided by the problem; our goal is to express 'dx' in terms of 't'
2) It's known that:

Thus, we have:

Then:

3) Finally, substituting all known values gives us:

After some calculations, the resulting work is:
161.9638 J.
4) To find power, we will use the following equation:

Thus
P = 161.9638/4.7 = 34.46 W