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Flauer
17 days ago
14

a stomp rocket takes 1.5 seconds to reach its maximum height what was the initial velocity and what was the maximum height ?

Physics
2 answers:
Ostrovityanka [3.2K]17 days ago
5 0
Here is the solution: 1) Let acceleration be a m/s^2 and velocity after 4 seconds be v m/s. According to v = u + at, we have v = 4a --------(i). For the first phase, applying s = ut + 1/2at^2 results in s1 = 0 + 1/2 x a (4)^2, yielding s1 = 8a ----------(ii). In the second phase, by using s = vt, we have s2 = 4a x (9.1-4), which results in s2 = 20.4a -----------(iii). Adding equations (ii) and (iii) gives us s1+s2 = 8a + 20.4a, leading to 100 = 28.4a, thus a = 3.52 m/s^2. For part 2(a), using v = u - gt gives 0 = u - 9.8 x 1.5, leading to u = 14.7 m/s. For part 2(b), using v^2 = u^2 - 2gh gives 0 = (14.7)^2 - 2 x 9.8 x h, resulting in h = 11.03 m. Thank you for your inquiry.
inna [3.1K]17 days ago
5 0
1) Vf = Vo - gt; Setting Vf = 0 gives Vo = gt, resulting in Vo = 9.8 m/s^2 * 1.5 s = 14.7 m/s. 2) The displacement is calculated as d = Vo*t - gt^2 / 2 = 14.7 m/s * 1.5 - 9.8 m/s^2 * (1.5 s)^2 / 2 = 11.02 m.
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Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

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moles of oxygen=\frac{47.8g*1mol}{16g}

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass=\frac{52.92 g}{5.975 mol}

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

3 0
1 month ago
A helicopter is traveling at 86.0 km/h at an angle of 35° to the ground. What is the value of Ax? Round your answer to the neare
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1) We will use the following equation to calculate work:

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