A glass tube is filled with hydrogen gas.  An electric current is passed through the tube, and the tube begins to glow a pinkish

a) Average velocity: 2.8 m/s

b) Average velocity: 5.2 m/s

c) Average velocity: 7.6 m/s

Explanation:

a)

The car's position over time t can be described by

where

To find the average velocity, we divide the displacement by the elapsed time:

At time t = 0, the position is:

At time t = 2.00 s, the position is:

This leads us to the displacement of

The duration for this interval is

Therefore, the average velocity during this period is

b)

At time t = 0, the position is:

At time t = 4.00 s, the position is:

Thus, the displacement is

The time interval is

This yields an average velocity of

c)

The position at t = 2 s is:

And at t = 4 s it is:

This gives us a displacement of

While the time interval is

So the resulting average velocity is

Find out more about average velocity:

Answer:

2.87 m

Explanation:

Given parameters:

Mass of the ball (m) = 60 g = 0.06 kg

Height of the tube (h) = 0.70 m

Force applied on the ball by compressed air (F) = 3.0 N

Initial velocity of the ball (u) = 0 m/s (Assumed)

Final velocity of the ball at the tube's exit (v) =?

Acceleration of the ball (a) =?

The ball's weight is derived from multiplying mass and gravity. Therefore,

Weight (W) =

Thus, the total force acting on the ball equals the net of upward force minus the weight.

Net force = Air force - Weight

According to Newton's second law, net force equals the mass multiplied by acceleration.

Acceleration (a) is calculated as 40.2 m/s².

Using the motion equation, we find:

Let’s denote the maximum height achieved as 'H'.

Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.

A decrease in kinetic energy equals an increase in potential energy.

Substituting the values, we solve for 'H', yielding:

Hence, the ball ascends to a height of 2.87 m above the top of the tube.

Density is defined as the mass divided by the volume.

You can alter the density of a substance by adjusting either its mass or volume.

Increasing the volume while maintaining a constant mass will result in a decrease in density (as the denominator of the fraction increases).

Furthermore, reducing the mass while keeping the volume the same will also lower the density (because the numerator is reduced).

Therefore, to achieve a lower density, you should either reduce the mass or increase the volume, keeping the other constant.

I hope this is helpful.

Answer:

Explanation:

To approach this problem, we need to understand two key concepts.

First, the gravitational force on an object in orbit equals its mass multiplied by centripetal acceleration.

Secondly, Newton's law of universal gravitation defines the force between two masses: Fg = mMG/r², where Fg denotes gravitational force, m and M signify the masses, G represents the gravitational constant, and r indicates the distance separating the two masses.

Thus:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

Potential energy for each planet is expressed as:

PE = mgr = m (MG/r²) r = mMG/r

Kinetic energy for each planet is computed as:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

Total mechanical energy is calculated as:

ME = PE + KE = 3/2 mMG/r

Since both planets share the same mass, the only variable is their orbital radius. Consequently, Planet A, with a smaller radius, possesses greater potential, kinetic, and mechanical energy.

Answer:

Explanation:

The stone reaches the top of the flagpole at both t = 0.5 s and t = 4.1 s

therefore, the total duration of the upwards motion above the peak of the pole is provided as

now we have

this indicates the speed at the flagpole's top

at this point we have

the height of the flagpole is stated as