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MaRussiya
5 days ago
13

A class contributed $8.40 in dimes and quarters to the Red Cross. In all, there were 45 coins. How many coins of each kind were

there?
Mathematics
1 answer:
tester [11.8K]5 days ago
6 0
Let d = number of dimes
Let q = number of quarters
45 = d + q
.1d +.25q = 8.40
We can apply the substitution method, starting with d = 45 - q.
Then substitute this d value into the second equation.
.1(45-q)+.25(q)=8.40
4.5-.1q+.25q=8.40
4.5+.15q = 8.40
.15q = 3.90
q = 26
d = 45 - 26 = 19
26 quarters
19 dimes
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Jay is letting her bread dough rise. After three hours, her bread dough is \dfrac{11}{5} 5 11 ​ start fraction, 11, divided by,
babunello [11299]
Jay's bread has risen to 220% of its initial size. The question, as it stands, is incomplete. What is missing would clarify: Jay's bread increases to 11/5 of its original size after three hours. To determine the percentage of its original size: New bread size = units when dough is at 11/5 of its original size.
6 0
12 days ago
A small-appliance manufacturer finds that the profit P (in dollars) generated by producing x microwave ovens per week is given b
PIT_PIT [11881]

Answer:

The amount of ovens that must be produced in a week to earn a $1610 profit is 70.

Step-by-step explanation:

Given:

A small-appliance manufacturer determines the profit P (in dollars) from producing x microwave ovens weekly by the formula:

P=\frac{1}{10}x(300-x)

with 0 ≤ x ≤ 200.

The target profit is $1610

So, set P = 1610, then solve for x:

1610=\frac{1}{10}x(300-x)

Multiply both sides by 10:

1610\cdot \:10=\frac{1}{10}x\left(300-x\right)\cdot \:10

16100=x\left(300-x\right)

16100=300x-x^2

-x^2+300x-16100=0

Next, factor the quadratic:

(x-70)(x-230)=0

Solving for x gives:

x=70,x=230

Since x=230 is outside the domain 0 ≤ x ≤ 200, we discard it.

Hence, the valid solution is x=70.

Therefore, to achieve a $1610 profit, the manufacturer must produce 70 ovens weekly.


7 0
1 month ago
When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t
zzz [11812]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

\boxed{u \ or \ v_i = initial \ velocity}

\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}

\boxed{a = acceleration \ (constant)}

\boxed{d = distance \ travelled}

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (m/s²)
  • u = initial speed = 0 m/s
  • v = takeoff velocity = 1.0 m/s
  • d = displacement = 0.50 mm

First, convert 0.50 mm to meters: \boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}

Solution steps:

Rearrange the formula to isolate acceleration (a).

\boxed{ \ v^2 = u^2 + 2ad \ }

\boxed{ \ v^2 - u^2 = 2ad \ }

\boxed{ \ 2ad = v^2 - u^2 \ }

\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }

Insert the given values into the rearranged equation.

\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }

\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }

\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }

\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }

This yields the flea's acceleration as 1,000 m/s².

Additional resources

  1. Scientific notation: brainly.com/question/7263463
  2. Determining substance mass: brainly.com/question/4053884
  3. Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

5 0
1 month ago
Read 2 more answers
WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the
Inessa [12133]

Answer:

a) P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

P(z>1.43)=1-P(z

b) P(X

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

P(z

c) P(

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

P(-1.43

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

X \sim N(15,3.5)

Where \mu=15 and \sigma=3.5

We seek the probability:

P(X>20)

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

z=\frac{x-\mu}{\sigma}

By applying this formula, we can find the probability:

P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

P(z>1.43)=1-P(z

Part b

P(X

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

P(z

Part c

P(

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

P(-1.43

5 0
1 month ago
Fruit juice comes in two types of containers. The first is a rectangular prism that is 9 inches tall and has a rectangular base
babunello [11299]

The volume of a rectangular prism:

V_p=Bh\\\\B=wl\\\\w=2\ in;\ l=3\ in;\ h=9\ in

insert

V_p=2\cdot3\cdot9=54\ in^3

The volume of a cylinder:

V_c=\pi r^2h\\\\r=1.5\ in;\ h=8\ in

insert:

V_c=\pi\cdot(1.5)^2\cdot8=\pi\cdot2.25\cdot8=18\pi\ in^3\approx18\cdot3.14=56.52\ in^3

Response: C. The cylinder possesses a larger volume.

3 0
13 days ago
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