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fenix001
3 days ago
10

Compare and contrast these isotopes: uranium -239, uranium -238, and uranium -235

Chemistry
2 answers:
eduard [2.6K]3 days ago
4 0
Each isotope contains an identical number of protons and electrons, but they vary in neutron count, making them isotopes.
VMariaS [2.8K]3 days ago
3 0

Response: They possess the same quantity of protons but vary in their number of neutrons.

Clarification:

Isotopes consist of atoms with an equal number of protons but differing neutron counts.

Uranium occupies the 92nd position in the periodic table.

The atomic numberindicates the number of protons present in an atom.

Atomic number = Number of protons

Mass numberrepresents the total of protons and neutrons found in an atom.

Mass number = Number of protons + Number of neutrons

For the isotopes mentioned: _{92}^{239}\textrm{U},_{92}^{238}\textrm{U}\text{ and }_{92}^{235}\textrm{U}

  • For _{92}^{239}\textrm{U}

Protons = 92

Neutrons = 239 - 92 = 147

  • For _{92}^{238}\textrm{U}

Protons = 92

Neutrons = 238 - 92 = 146

  • For _{92}^{235}\textrm{U}

Protons = 92

Neutrons = 235 - 92 = 143

Thus, they share the same number of protons but vary in their neutron counts.

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lorasvet [2668]

Respuesta:

Un avión fabricado con aluminio puede transportar una mayor cantidad de pasajeros comparado con uno de acero.

Explicación:

La masa total que el avión es capaz de levantar es:

m_{tot}=m_{fuselage}+m_{passangers}

Para el aluminio:

m_{tot}=m_{fus-Al}+m_{pas-Al}

m_{fus-Al}=\delta _{Al}*V_{fuselage}

y

V_{fuselage}=\frac{\pi *L}{4}*[D^2-(D-e)^2]

donde:

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m_{tot}=\delta _{Al}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Al}

Para el acero (mismo procedimiento):

m_{tot}=\delta _{Steel}*\frac{\pi *L}{4}*[D^2-(D-e)^2]+m_{pas-Steel

Sabiendo que la masa total que el avión puede levantar es constante y que el aluminio tiene una densidad menor que la del acero, podemos afirmar que el avión de aluminio puede levantar un mayor número de pasajeros.

También es posible estimar un peso promedio de los pasajeros para calcular cuántos podría soportar.

5 0
1 month ago
Hydrogen gas has a density of 0.090 g/L, and at normal pressure and -1.72 C one mole of it takes up 22.4 L. How would you calcul
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Answer:

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Explanation:

Assuming all calculations occur at standard pressure and a temperature of -1.72°C :

n= \frac{m}{ \rho }* \frac{1 mol}{22.4 L}

Where

n is the number of moles of hydrogen

n is the mass of hydrogen

\rho is the density of hydrogen

6 0
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How many grams of mercury are present in a barometer that holds 6.5mL of mercury? ...?
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<span>13.6
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Neither dry soil nor pure water conducts electricity. But wet soil will conduct electricity. Explain why this happens?
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