Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)
Number of electrons transferred, n=2. Equilibrium constant,
K=2.69×10∧12
ΔG=-2.303RT logK
R=gas constant=8.314J/mol-k
T= temperature in K= 25°C=25+273=298K
Calculating gives us ΔG = -70922.3J. However, ΔG = -nFE
n= number of electrons transferred in the reaction =2
F= faraday = 96500C
E=cell potential is what?
∴E = ΔG.nF
=-(-70922.3)/2×96500)
=0.367V.
Utilize the ideal gas law:
n = PV / RT
P = 100kPa = 100 x 1000 x (9.8 x 10^{-6}) = 0.98 atm
Convert kPa to atm, where 1 Pa = 9.8 x 10^{-6} atm.
T = 293 K
V = 6.8 L
R = 1/12
Substituting all values leads to:
n = 0.272
1 percent of the solar radiation
Answer: The right choice is (c) application of both a mobile phase and a stationary phase.
Explanation:
Chromatography: This refers to a technique for separating a mixture where the mixture is distributed between two phases at varying rates, one being stationary and the other moving.
Mobile phase: The component in which the mixture is dissolved is referred to as the mobile phase.
Stationary phase: This is an adsorbent medium that remains in place while a liquid or gas passes over its surface, thus remaining stationary.
Consequently, a key characteristic of any chromatography technique involves utilizing both a mobile and a stationary phase.
Answer:
1.2×10²³ atoms.
Explanation:
In the problem, we see the data:
Mole of propanone = 0.20 mole
Calculating the number of atoms in propanone =?
According to Avogadro's principle, one mole of a substance contains 6.022×10²³ atoms.
This means that one mole of propanone also holds 6.022×10²³ atoms.
Thus, we can determine the atom count in 0.20 mole of propanone as:
1 mole of propanone contains 6.022×10²³ atoms.
Accordingly, 0.20 mole of propanone will have = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.
Therefore, 0.20 mole of propanone contains
1.2×10²³ atoms.
