The enthalpy change associated with the precipitation reaction is 84 kJ/mole
Why?
The chemical equation for the reaction can be written as
AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)
To determine the enthalpy change, the following equation applies

To calculate the heat (Q):

Next, we need to calculate the number of moles involved in the reaction (n):
![n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles](https://tex.z-dn.net/?f=n%3D%5BAgNO_3%5D%2Av%28L%29%3D%280.1M%29%2A%280.05L%29%3D0.005moles)
With these two values, we can substitute them into the first equation:

Have a great day!