Hypothesis: The liquid will project far.
Independent Variable: Height of the hole.
Dependent Variable: Distance of the squirt.
Constant: All other factors aside from the independent variable, such as the liquid volume.
Control: None that I recognize.
Number of groups: 4
Trials per group: 4
Response:
45cm
Clarification:
A converging mirror is generally termed a concave mirror. The focal length and the image distance for a concave mirror are both expressed as positive values.
Using the mirror formula to derive the object distance;

Where f denotes the focal length, u indicates the object distance, and v represents the image distance.
Given f = 30cm, and v = 2u (The formed image is double the size of the pencil)
Plugging these values into the formula to solve for u yields;

By cross-multiplying, we obtain;
2u = 90
Dividing both sides by 2;
2u/2 = 90/2
u = 45cm
The object's distance from the mirror measures 45cm
The question pertains to the change in frequency of a wave noted by an observer moving in relation to the source, indicating that the concept to invoke is "
Doppler's effect."
The standard formula for the Doppler effect is:

-- (A)
Note that we don’t need to be concerned with the signs here, as all entities are moving toward each other. If something was moving away, a negative sign would apply, but that is not relevant to this scenario.
Where,
g = Speed of sound = 340m/s.

= Velocity of the observer relative to the medium =?.

= Velocity of the source in relation to the medium = 0 m/s.

= Frequency emitted from the source = 400 Hz.

= Frequency recognized by the observer = 408 Hz.
Substituting the given values into equation (A) will yield:


Solving the above will result in,

= 6.8 m/s
The correct result = 6.8m/s
assuming north-south is along the Y-axis and east-west along the X-axis
X = total X-displacement
from the graph, total displacement in the X-direction is computed as
X = 0 - 20 + 60 Cos45 + 0
X = 42.42 - 20
X = 22.42 m
Y = total Y-displacement
from the graph, total displacement in the Y-direction is computed as
Y = 40 + 0 + 60 Sin45 + 50
Y = 90 + 42.42
Y = 132.42 m
To calculate the magnitude of the net displacement vector, we apply the Pythagorean theorem, yielding
magnitude: Sqrt(X² + Y²) = Sqrt(22.42² + 132.42²) = 134.31 m
Direction: tan⁻¹(Y/X) = tan⁻¹(132.42/22.42) = 80.4 deg north of east
Calculating the average speed is straightforward by using the formula involving distance and time:
average speed = distance / time
Thus, we have:
average speed = 4875 ft / 6.85 minutes
<span>average speed = 711.68 ft / min</span>