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ruslelena
4 days ago
10

A parachutist, after opening her parachute, finds herself gently floating downward, no longer gaining speed. She feels the upwar

d pull of the harness, while gravity pulls her down. Which of these two forces is greater? Or are they equal in magnitude?
Physics
1 answer:
Sav [3K]4 days ago
5 0

As the parachutist is descending at a steady rate

we can conclude that

a = \frac{dv}{dt}

Acceleration indicates the change in velocity

given the constant velocity in this scenario

a = 0

Thus, in this situation, we find the acceleration to be zero

It’s understood from Newton's second law

F_{net} = ma

where a is equal to 0

F_{net} = 0

F_{net} = F_g - F_b

Here, the force due to gravity

equals the force due to buoyancy

F_gHence, we can deduce

F_b

therefore

F_g - F_b = 0

as such the upward force is counteracted by the downward force.

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All the weight of the wooden board rests solely on the support situated at the center of the rod, while the other support positioned at one end experiences no reaction force, resulting in a 0 reaction force.

Thus, the reaction force at the central support corresponds to the weight of the board, whereas the end support has 0 reaction force.

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Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of
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13 days ago
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An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista
Sav [3045]

Answer:

        h = 12.8 cm

Explanation:

The initial parameters are as follows:

distance = 6.4 cm

  • when the object descends, its weight matches the spring's force

        weight = spring force

         mg = ky... equation 1

  • potential energy stored in a stretched spring = work done by the spring

        mgh = 0.5 x k x h^{2}....equation 2

  • Substituting from equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

                2y = h

  • where y is 6.4, yielding the maximum elongation as

          h = 2 x 6.4 = 12.8 cm

6 0
1 month ago
A water jet that leaves a nozzle at 60 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets lo
Ostrovityanka [3082]

Response:

216000 W or 216 kW

Details:

Power: This refers to the rate at which energy is utilized or consumed. The standard unit for power is the Watt (W).

In general,

Power = Energy/time

P = E/t........................ Equation 1.

However,

E = 1/2mv²..................... Equation 2

with m representing mass, and v indicating velocity.

Substituting equation 2 into equation 1,

P = 1/2mv²/t...................... Equation 3

Assuming flow rate (Q) = m/t,

Q = m/t................ Equation 4

Insert equation 4 into equation 3,

P = Qv²/2........................ Equation 5

Where Q stands for flow rate, v is velocity, and P denotes power.

Given: Q = 120 kg/s, v = 60 m/s

Plug these values into equation 5,

P = 120(60)²/2

P = 60(60)²

P = 60×3600

P = 216000 W.

Thus, the potential power generation of the water jet is 216000 W or 216 kW.

5 0
1 month ago
A sled of mass m is being pulled horizontally by a constant horizontal force of magnitude F. The coefficient of kinetic friction
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The average velocity of the sled can be expressed with the formula vavg = s/t. Hello! The calculation for average velocity involves determining the distance traveled over time. Thus, vavg = Δx/Δt, where vavg represents average velocity, Δx is the distance traversed, and Δt is the duration of time taken. We know both the distance (s) and the time (t) required for the sled to cover that distance, which allows us to compute the average velocity using the formula vavg = s/t. Wishing you a great day!
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