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labwork
12 days ago
5

f a stadium pays $11,000 for labor and $7,000 for parking, what would the stadium's parking revenue have to be if the stadium is

hoping parking labor is 6% of parking revenue? a) $116,666 b) $183,333 c) $189,400 d) $190,000
Physics
2 answers:
serg [1.1K]12 days ago
8 0

Answer: B

183,333

Explanation:

Simply because I stated so.

Yuliya22 [1.1K]12 days ago
7 0

Answer:

Explanation:

a

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A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108
Ostrovityanka [942]

Answer: The calorimeter's heat capacity is 6.72J/g^oC

Explanation:

This scenario assumes the amount of heat lost by the hot object equals the amount of heat gained by the cold object.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat capacity of water = 4.184J/g^oC

c_2 = specific heat capacity of calorimeter =?

m_1 = mass of water = 108.7 g

m_2 = mass of calorimeter = 108.7 g

T_f = final temperature of the mixture = 35.0^oC

T_1 = initial temperature of the water = 60.2^oC

T_2 = initial temperature of calorimeter = 19.3^oC

Now substituting all provided values into the formula, we obtain

(108.7g)\times (4.184J/g^oC)\times (35.0-60.2)^oC=-(108.7g)\times c_2\times (35.0-19.3)^oC

c_2=6.72J/g^oC

Hence, the heat capacity of the calorimeter is 6.72J/g^oC

3 0
9 days ago
Two frictionless lab carts start from rest and are pushed along a level surface by a constant force. Students measure the magnit
Yuliya22 [1153]

Answer:

The kinetic energy is higher for the first cart.

Explanation:

For the second cart, its mass is 2kg and the momentum measured is 10kg m/s, which leads to

(2kg)v = 10kg\: m/s

resulting in

v = 5m/s.

Consequently, the kinetic energy for the 3kg cart ends up as

K.E.  = \dfrac{1}{2}mv^2

= \dfrac{1}{2}(2kg)(5m/s)^2 =  25J

\boxed{K.E = 25J}

indicating it is less than that of the 1kg cart so it follows that the first cart possesses greater kinetic energy.

3 0
15 days ago
A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
Keith_Richards [1021]
I will assume the girl is on the right while the boy is on the left.
The net force represents the total of all forces acting on an object, factoring in negatives.
Let the force from the boy be denoted as b. We’ll apply the formula F = ma.

b + 3.5 = 0.2(2.5)

This reduces to a straightforward algebraic problem. By solving, we find that the boy is applying a force of -3N to the left.
5 0
1 day ago
Read 2 more answers
A man makes a 27.0 km trip in 16 minutes. (a.) How far was the trip in miles? (b.) If the speed limit was 55 miles per hour, wa
Maru [1053]

Answer:

(a) 16.777 miles

(b) Yes, he exceeded the speed limit

Explanation:

(a)

We need to perform the necessary calculations to convert kilometers to miles:

27km*\frac{1000m}{1km} *\frac{1mi}{1609.34m} =16.77706389mi

Thus, the distance of the trip in miles is:

d=16.77706389mi

(b)

Next, we will compute the man's speed during the journey:

v=\frac{d}{t}

Before that, we must convert minutes to hours:

16min*\frac{1h}{60min} =2.666666667h

The resulting speed is:

v=\frac{16.77706389mi}{2.666666667h} =62.91398959\frac{mi}{h}

Consequently:

62.91398959\frac{mi}{h}>55\frac{mi}{h}

Thus, it can be concluded that the driver was speeding

8 0
15 hours ago
Frank wrote several statements to summarize the relationship between the first and second laws of thermodynamics. 1 - Thermal en
Maru [1053]
According to the second law, heat, often called thermal energy, cannot be entirely turned into work.
The second statement is closely tied to this law.
We can conclude that some energy dissipates while some is used for work.
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10 days ago
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