f a stadium pays $11,000 for labor and $7,000 for parking, what would the stadium's parking revenue have to be if the stadium is
2 answers:
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Answer:
The work done, W = 19.6 J
Explanation:
It’s provided that
The mass of the block, m = 5 kg
The velocity of the block, v = 10 m/s
The coefficient of kinetic friction between the block and rough surface is 0.2
Distance traveled by the block, d = 2 m
As the block traverses the rough section, it loses energy equal to the work done by the kinetic energy.
W = 19.6 J
Thus, the change in kinetic energy of the block moving through the rough section is 19.6 J. Consequently, this is the required answer.
Response:
Explanation:
Let T denote the tension.
By employing Newton's second law to analyze the bucket's downward motion, we have:
mg - T = ma
A torque, TR, acts on the drum, inducing an angular acceleration α in it. If I refers to the moment of inertia of the drum, then:
TR = Iα
Rearranging gives: TR = Ia/R
This leads to T = Ia/R²
Substituting this expression for T back into the previous equation yields:
mg - T = ma
mg - Ia/R² = ma
Consequently, we find that mg = Ia/R² + ma
Therefore, a (I/R² + m) = mg
This results in: a = mg / (I/R² + m)
Next, we aim to express T as:
mg - T = ma
which simplifies to mg - ma = T
Rearranging gives mg - m²g / (I/R² + m) = T
Thus, we arrive at: mg - mg / (1 + I / m R²) = T
For part (b), T = Ia/R²
and for part (c), the moment of inertia of a hollow cylinder calculates to:
I = 1/2 M (R² - (R² / 4))
This simplifies to 3/4 x 1/2 MR², yielding 3/8 MR²
Thus, I / R² = 3/8 M
When we substitute, we find a = mg / (3/8 M + m)
and subsequently T = Ia/R²
= 3/8 MR² × mg / (3/8 M + m) × 1/R²
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