Answer:The charges on the inner and outer surfaces of the shell are +q and -q, respectively
Explanation:
In static equilibrium within a conductor, the total electric field, denoted as E, equals zero
This indicates that no charge can be in motion, maintaining the static state of equilibrium within the conductor.
Since the Electric field, E remains zero, the flux through the shell’s surface is also zero.
According to Gauss' law, the total enclosed charge must be zero.
Given that the center of the shell has a charge of -q, the positive charge on the inner surface must be +q in order for the total charge enclosed to balance out to zero.
As the charge resides in static equilibrium, there will be a corresponding negative charge on the outer surface, which totals to -q.
This leads us to the conclusion that the charges on the inner and outer surfaces of the shell are +q and -q, respectively
You would gain an additional 40/60 of energy, which equals 2/3. To find the actual energy consumption, multiply 5/3 by the needed energy.
Respuesta:
11.4 m/s
Explicación:
La fórmula para la aceleración centrípeta es:
donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.
En este problema,
a = g = aceleración debida a la gravedad en la cima = 
v = ?
R = 13.2 m
Por lo tanto,
v = 11.4 m/s
Response:
210.3 degrees
Justification:
The total force acting on charge A is 59.5 N
Apply the x and y components of the net force to determine the direction
atan (y/x)
