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labwork
1 month ago
5

f a stadium pays $11,000 for labor and $7,000 for parking, what would the stadium's parking revenue have to be if the stadium is

hoping parking labor is 6% of parking revenue? a) $116,666 b) $183,333 c) $189,400 d) $190,000
Physics
2 answers:
serg [3.5K]1 month ago
8 0

Answer: B

183,333

Explanation:

Simply because I stated so.

Yuliya22 [3.3K]1 month ago
7 0

Answer:

Explanation:

a

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Write a hypothesis about the effect of increasing voltage on the current in the circuit. Use the "if . . . then . . . because .
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Hypothesis: An increase in voltage should result in a corresponding rise in current because according to Ohm's Law,

I \propto V

I=\frac{V}{R}

Ohm's Law indicates that current is proportional to voltage when resistance remains constant. Hence, if resistance stays the same, elevating the voltage will lead to an increase in current. Conversely, if voltage remains unchanged and resistance increases, current will decrease.

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A person drops a stone down a well and hears the echo 8.9 s later. if it takes 0.9 s for the echo to travel up the well, approxi
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The total duration from the stone's drop to the echo being heard is 8.9 seconds. The sound takes 0.9 seconds to reach the listener, meaning it takes the stone 8 seconds to descend to the well's bottom. Using gravitational acceleration, the well's depth calculates to be approximately 313.6 meters.
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A car with an initial velocity of 16.0 meters per second east slows uniformly to 6.0 meters per second east in 4.0 seconds. What
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A person is rowing across the river with a velocity of 4.5 km/hr northward. The river is flowing eastward at 3.5 km/hr (Figure 4
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Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.

Explanation:

Let Q be the speed of the boat, and P be the speed of the river flow.

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According to vector addition using the law of triangles:

R=\sqrt{P^2+Q^2+2PQCos\theta}

From the diagram:

P = 3.5 km/h, Q = 4.5 km/h

\theta= 90^o

R=\sqrt{P^2+Q^2+2PQCos\theta}=\sqrt{(3.5)^2+(4.5)^2+3.5\times 4.5\times cos90^o}=5.70

(Cos90^o=0),(sin 90^o=1)

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Therefore, her velocity magnitude relative to the shore is 5.70 km/h.

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