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lisov135
3 months ago
13

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

s 13.2 m, with what minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top? Assume the rider is not strapped to the car. Group of answer choices 10.1 m/s 11.4 m/s 14.9 m/s 12.5 m/s
Physics
1 answer:
Sav [3.1K]3 months ago
8 0

Respuesta:

11.4 m/s

Explicación:

La fórmula para la aceleración centrípeta es:

a=\frac{v^2}{R}

donde, a es la aceleración, v la velocidad alrededor de la circunferencia y R el radio del círculo.

En este problema,

a = g = aceleración debida a la gravedad en la cima = 9.81\ m/s^2

v = ?

R = 13.2 m

Por lo tanto,

9.81=\frac{v^2}{13.2}

v^2=9.81\times {13.2}

v = 11.4 m/s

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