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klasskru
3 months ago
14

Bonnie and clyde are sliding a 300 kg bank safe across the floor to their getaway car. the safe slides with a constant speed if

clyde pushes from behind with 445 n of force while bonnie pulls forward on a rope with 350 n of force. what is the safe's coefficient of kinetic friction on the bank floor?
Physics
1 answer:
inna [3.1K]3 months ago
3 0
<span>We can sketch a free body diagram of the safe to depict all horizontal forces involved: Clyde's force, Bonnie's force, and friction. Since the safe moves at a steady speed (zero acceleration), the sum of forces equals zero. 0 = Clyde's force + Bonnie's force - friction Friction equals the sum of Clyde's and Bonnie's forces μ mg = Clyde's force + Bonnie's force Rearranged: μ = (Clyde's force + Bonnie's force) / (mg) Substituting values: μ = (445 N + 350 N) / (300 kg × 9.80 m/s²) μ = 0.27 Therefore, the coefficient of kinetic friction is 0.27</span>
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Explanation:

Elements are organized by their atomic numbers on the periodic table. Those in the same vertical column (known as groups) exhibit the same valence electron configurations, resulting in similar chemical characteristics. Consequently, there are numerous elements sharing analogous chemical properties grouped with Bromine.

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A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second; and the m
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Answer:

(A) The tension's magnitude grows to four times the initial value, 4F.

Explanation:

When an object travels in a circular path, a centripetal force is exerted upon it. In this instance, the centripetal force acting on the stone can be represented by \frac { m{ v }^{ 2 } }{ r }.

                   Here, m denotes the mass of the object

                               v is the velocity or speed of the object

                               r signifies the radius of the circular path

Importantly, the tension corresponds to the centripetal force.

Initially, the string completes one revolution each second, and subsequently, it accelerates to perform two revolutions in the same time frame. This signifies that the speed has increased twofold.

Applying our formula:F =\frac { m{ v }^{ 2 } }{ r }

                               where F indicates the tension in the string

assuming the starting speed is v, after doubling it becomes 2v

Maintaining the circle's radius, we arrive at:

F=\frac { m{ (2v) }^{ 2 } }{ r } =\frac { 4m{ v }^{ 2 } }{ r }

From this equation, it's clear that the initial tension has quadrupled.

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A girl and boy pull in opposite directions on a stuffed animal. The girl exerts a force of 3.5 N. The mass of the stuffed animal
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I will assume the girl is on the right while the boy is on the left.
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Response:

The work performed by the particle traveling from x = 0 to x = 2 m totals 20 J.

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The force impacting a particle, which is restricted to the x-axis, is expressed as follows:

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