Consider a box sitting in the back of a pickup. The pickup accelerates to the right, and because the bed of the pickup is sticky

The required lift force is approximately 866.92 N. To determine this, we first establish the shark's mass at 92 kg and its density at 1040 kg/m³. The volume of the shark is calculated by dividing mass by density, yielding 0.08846 m³. The buoyant force acting on the shark is then determined by multiplying the volume by the density of water and gravity, resulting in a lift force of 866.92 N.

The answer is 30 seconds.

Answer:

2.87 m

Explanation:

Given parameters:

Mass of the ball (m) = 60 g = 0.06 kg

Height of the tube (h) = 0.70 m

Force applied on the ball by compressed air (F) = 3.0 N

Initial velocity of the ball (u) = 0 m/s (Assumed)

Final velocity of the ball at the tube's exit (v) =?

Acceleration of the ball (a) =?

The ball's weight is derived from multiplying mass and gravity. Therefore,

Weight (W) =

Thus, the total force acting on the ball equals the net of upward force minus the weight.

Net force = Air force - Weight

According to Newton's second law, net force equals the mass multiplied by acceleration.

Acceleration (a) is calculated as 40.2 m/s².

Using the motion equation, we find:

Let’s denote the maximum height achieved as 'H'.

Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.

A decrease in kinetic energy equals an increase in potential energy.

Substituting the values, we solve for 'H', yielding:

Hence, the ball ascends to a height of 2.87 m above the top of the tube.