A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b
y the system? (1 l·atm = 101.3 j)
2 answers:
The amount of work performed by a system at consistent pressure is defined by the following equation:
where
p represents pressure
as the final volume
as the initial volume
Plugging the values given in this case into the formula gives us
Considering that
, the result for the work done becomes
where
p represents pressure
Plugging the values given in this case into the formula gives us
Considering that
The system has done work of approximately 101.3 J
Additional explanation
To revisit Work Done by Ideal Gas formula can be expressed as:
where:
P = Gas Pressure ( Pa )
V = Gas Volume ( m³ )
Next, let us look at the problem!
Given:
initial volume of system = Vo = 1.00 L
final volume of system = V = 2.00 L
constant external pressure = P = 1.00 atm
What we need to find is:
work done by the system = W =?
Solution:
← Constant External Pressure
←
to Joule
Conclusion:
The system's work amounts to approximately 101.3 J
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Answer details
Grade: High School
Subject: Physics
Chapter: Pressure
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Answer:
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Explanation:
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where m represents mass,
is the initial speed before impact,
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are the velocities of the impacted object after the collision and of the originally stationary object after the impact.
Thus,
After the collision, the kinetic energy doubles, therefore:
Substituting the initial velocity of 5 m/s provides the equation needed to proceed.
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leads to
Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25.
By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.
