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3 months ago

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A system expands from a volume of 1.00 l to 2.00 l against a constant external pressure of 1.00 atm. what is the work (w) done b

y the system? (1 l·atm = 101.3 j)

2 answers:

Keith_Richards [3.2K]3 months ago

8 0

The amount of work performed by a system at consistent pressure is defined by the following equation:
$W=p \Delta V = p (V_f - V_i)$
where
p represents pressure
$V_f$ as the final volume
$V_i$ as the initial volume

Plugging the values given in this case into the formula gives us
$W=p (V_f -V_i)=(1.00 atm)(2.00 L-1.00 L)=1.00 L\cdot atm$

Considering that $1 atm \cdot L = 101.3 J$ , the result for the work done becomes
$W= 1.00 atm \cdot L = 101.3 J$

Softa [3K]3 months ago

6 0

The system has done work of approximately 101.3 J

$\texttt{ }$

Additional explanation

To revisit Work Done by Ideal Gas formula can be expressed as:

$\boxed{ W = \int {P} \, dV }$

where:

P = Gas Pressure ( Pa )

V = Gas Volume ( m³ )

Next, let us look at the problem!

$\texttt{ }$

Given:

initial volume of system = Vo = 1.00 L

final volume of system = V = 2.00 L

constant external pressure = P = 1.00 atm

What we need to find is:

work done by the system = W =?

Solution:

$W = \int {P} \, dV$

$W = P \Delta V$ ← Constant External Pressure

$W = P ( V - V_o )$

$W = 1.00 ( 2.00 - 1.00 )$

$W = 1.00 ( 1.00 )$ ←

Convert from

$W = 1.00 \texttt{ L.atm}$

L.atm

$W = 1.00 \times 101.3 \texttt{ J}$ to Joule

$\boxed {W = 101.3 \texttt{ J} }$

$\texttt{ }$

Conclusion:

The system's work amounts to approximately 101.3 J

$\texttt{ }$

Learn more

Buoyant Force:

Kinetic Energy:

Volume of Gas:

Impulse:
Gravity:

$\texttt{ }$

Answer details

Grade: High School

Subject: Physics

Chapter: Pressure

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