Answer:
Total bandwidth: 8 kHz
Explanation:
Data provided:
Transmitter frequency: 3.9 MHz
Modulation up to: 4 kHz
Solution:
For the upper side frequencies:
Upper side frequencies = 3.9 × + 4 × 10³
Upper side frequencies = 3.904 MHz
For the lower side frequencies:
Lower side frequencies = 3.9 × - 4 × 10³
Lower side frequencies = 3.896 MHz
Consequently, the total bandwidth is computed as:
Total bandwidth = upper side frequencies - lower side frequencies
Total bandwidth = 8 kHz
Answer:
Change in length = 0.0913 in
Explanation:
Given data:
Length = 6 ft
Diameter = 0.2 in
Load w = 200 lb/ft
Solution:
We start by applying the equilibrium moment about point C, expressed as
∑M(c) = 0.............1
This can be used to find the force in AB.
10× 200 × ( 5) - (T cos(30)) × 10 = 0
Solving gives us
Tension in wire T(AB) = 1154.7 lb
We also know the modulus of elasticity for A992 is
E = 29000 ksi
And the area will be
Area =
The change in length is expressed as
Change in length = .........2
Substituting values results in
Change in length =
Change in length = 0.0913 in
Answer:
The power of the pump is 23.09 kW.
Explanation:
Parameters
gravitational constant,
mass flow rate,
flow density,
efficiency of the pump,
output gauge pressure,
input gauge pressure,
cross-sectional area of output pipe,
cross-sectional area of input pipe,
height of discharge, (evaluated at pump’s maximum height of 1.22 m)
input height,
hydraulic power of the pump,
Initially, the volumetric flow (Q) needs to be determined
Next, compute the velocity (v) for both input and output
Subsequently, the total head (H) can be calculated
Finally, the computation of pump power is done as follows
Response:
The cutting speed is calculated at 365.71 m/min
Clarification:
Given parameters include
diameter D = 250 mm
length L = 625 mm
Feed f = 0.30 mm/rev
cut depth = 2.5 mm
n = 0.25
C = 700
To find
the cutting speed that ensures the tool life coincides with the cutting time for the three parts
The formula for cutting time is given as
Tc =
....................1where D refers to diameter, L refers to length and f refers to feed while V represents speed
Tc =
Tc =
Given the tool life is expressed as
T = 3 × Tc............................2
where T denotes tool life and Tc is the cutting duration
Calculating tool life by substituting values into equation 2 yields
T = 3 ×
This yields V = 365.71
Thus, the cutting speed calculates to 365.71 m/min