An open vat in a food processing plant contains 500 L of water at 20°C and atmospheric pressure. If the water is heated to 80°C,
1 answer:
Answer:
Volume change percentage is 2.60%
Water level increase is 4.138 mm
Explanation:
Provided data
Water volume V = 500 L
Initial temperature T1 = 20°C
Final temperature T2 = 80°C
Diameter of the vat = 2 m
Objective
We aim to determine percentage change in volume and the rise in water level.
Solution
We will apply the bulk modulus equation, which relates the change in pressure to the change in volume.
It can similarly relate to density changes.
Thus,
E = ................1
And ............2
Here, ρ denotes density. The density at 20°C = 998 kg/m³.
The density at 80°C = 972 kg/m³.
Plugging in these values into equation 2 gives
dV = 0.0130 m³
Therefore, the percentage change in volume will be
dV % = × 100
dV % = × 100
dV % = 2.60 %
Hence, the percentage change in volume is 2.60%
Initial volume v1 = ................3
Final volume v2 = ................4
From equations 3 and 4, subtract v1 from v2.
v2 - v1 =
dV =
Substituting all values yields
0.0130 =
Thus, dl = 0.004138 m.
Consequently, the water level rises by 4.138 mm.
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Answer:
a) , b)
Explanation:
a) The uniform dresser can be modeled using specific equilibrium equations:
Following some algebraic manipulations, the formulated equation is derived:
b) Similarly, the man can be represented by a set of equilibrium equations:
After some algebraic changes, the expression for the coefficient of static friction comes out as:
Answer:
The duration is 17.43 minutes.
Explanation:
Based on the provided information, the initial diameter is 5 m
the velocity is 3 m/s
and the final diameter is 17 m.
To find the solution, we will use the volume change equation expressed as
ΔV = .............1
where ΔV represents the change in volume, rf is the final radius, and ri is the initial radius.
Calculating ΔV yields
ΔV =
ΔV = 2507 m³.
Thus,
Q = velocity × Area
Q = 3 × π ×(0.5)² = 2.356 m³/s.
Next, the change in time can be expressed as
Δt =
Δt =
Δt = 1046 seconds.
Therefore, the total change in time amounts to 17.43 minutes.