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Elina
1 month ago
10

A physicist is constructing a solenoid. She has a roll of insulated copper wire and a power supply. She winds a single layer of

the wire on a tube with a diameter of dsolenoid = 10.0 cm. The resulting solenoid is ℓ = 60.0 cm long, and the wire has a diameter of dwire = 0.100 cm. Assume the insulation is very thin, and adjacent turns of the wire are in contact. What power (in W) must be delivered to the solenoid if it is to produce a field of 6.40 mT at its center? (The resistivity of copper is 1.70 ✕ 10−8 Ω · m.)
Physics
1 answer:
ValentinkaMS [3.4K]1 month ago
5 0
The power required is P = 105.44 W. From the provided data: Diameter D = 10 cm, Length L = 60 cm, wire diameter d = 0.1 cm, magnetic field strength B = 6.4 mT, and resistivity of copper ρ = 1.7 x 10⁻⁸ Ω·m. The turns in the solenoid N can be found using N = L/d, thus N = 60/0.1 = 600 turns. The total length of the wire is Lc = πDN, calculated as Lc = 3.14 x 0.1 x 600 equaling 188.4 m. Current I is determined as I = 5.09 A, and the resistance R is identified as R = 4.07 Ω. The power P is then calculated using the formula P = I²R, thus P = 5.09² x 4.07 W results in P = 105.44 W.
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Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance
kicyunya [3294]

Response:

Clarification:

The force between two charges, q₁ and q₂ at a distance d is represented by the formula

F = k q₁ q₂ / d²

Here, the force between charge q₁ = -15 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C with distance d = (1.66 - 1.24) = 0.42 mm

k = 1 / (4π x 8.85 x 10⁻¹²)

Substituting the values into the equation

F = 1 / (4π x 8.85 x 10⁻¹²) x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²

= 9 x 10⁹ x -15 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²

= 35969.4 x 10⁻³ N.

For the force between charge q₂ = 34.5 x 10⁻⁹ C and q₃ = 47 x 10⁻⁹ C at a distance d = (1.24 - 0) = 1.24 mm.

Substituting the values into the expression

F = 1 / (4π x 8.85 x 10⁻¹²) x 34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²

= 9 x 10⁹ x -34.5 x 10⁻⁹ x 47 x 10⁻⁹ / (0.42 x 10⁻³)²

= 82729.6 x 10⁻³ N

Both forces direct towards the left (away from the origin, towards the negative x-axis)

Total force = 118699 x 10⁻³

= 118.7 N.

5 0
1 month ago
A motorcycle traveling at 36 m/s slams on the brakes to avoid an accident. The motorcycle skids 23m before stoping. What is the
ValentinkaMS [3465]
Since the motorcycle was at a speed of 36 m/s prior to braking, that marks the initial velocity.
u = 36 {ms}^{ - 1}
The motorcycle skidded 23m before coming to a full stop, indicating that
s = 23m
As it has ceased motion, the final velocity is zero.

v = 0{ms}^{ - 1}
We can apply the 'suvat' formula relevant to linear motion.

{v}^{2} = {u}^{2} + 2as
Substituting the aforementioned values allows us to find,

{0}^{2} = {36}^{2} + 2a(23)


0 = 1296+ 46a
46a = - 1296
a = - 28.2 {ms}^{ - 2}


We can apply the formula
v = u + at
to calculate the time required for the motorcycle to stop.

0 = 36 + - 28.2t
- 36 = - 28.2t
t = 1.3s
8 0
2 months ago
A table tennis ball with a mass of 0.003 kg and a soccer ball with a mass of 0.43 kg or both Serta name motion at 16 M/S calcula
Maru [3345]
To begin, let's state the facts: the tennis ball weighs 0.003 kg, while the soccer ball weighs 0.43 kg, and both are moving at the same speed of 16 m/s. The formula for momentum is P=MV where P stands for Momentum, M for Mass, and V for Velocity. Now, let's calculate the momentum for the tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ). I denote tennis ball momentum with a subscript "t." For the soccer ball, the momentum is Ps= 0.43 x 16 m/s = (      km-m/s). When we assess the momentum between the two balls, the heavier one will typically exhibit more momentum owing to its greater mass, unless the tennis ball, having less mass, achieves a higher velocity to match or exceed the momentum of the soccer ball.
8 0
2 months ago
Read 2 more answers
A resultant vector is 8.00 units long and makes an angle of 43.0 degrees measured ������� – ��������� with respect to the positi
Maru [3345]

Answer:

223 degrees

Explanation:

We have the following information:

Magnitude of the resultant vector = 8 units

The resultant vector makes a counterclockwise angle with the positive x-axis

\theta=43^{\circ}

Our goal is to determine the magnitude and angle of the equilibriant vector.

We understand that the equilibrium vector has the same magnitude but is oriented in the opposite direction of the given vector.

Thus, the equilibrium vector's magnitude = 8 units

x-component of a vector=v_x=vcos\theta

Where v = Magnitude of vector

Using the formula:

x-component of the resultant vector=v_x=8cos43=5.85

y-component of the resultant vector=v_y=vsin\theta=8sin43=5.46

x-component of the equilibrium vector=v_x=-5.85

y-component of the equilibrium vector=-v_y=-5.46

Because the equilibrium vector lies in the third quadrant

\theta=tan^{-1}(\frac{v_x}{v_y})=tan^{-1}(\frac{-5.46}{-5.85})=43^{\circ}

The angle \theta' is in the third quadrant

In the third quadrant, the angle =\theta'+180^{\circ}

The angle of the equilibrium vector measured from the positive x-axis in a counterclockwise direction is 180+43=223 degrees

4 0
2 months ago
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