Using your hand to exert a horizontal force, you push a physics textbook across the floor at a steady pace. The frictional force

Response:

E =  ρ ( R1²) / 2 ∈o R

Clarification:

Provided information

Two cylinders are aligned parallel

Distance = d

Radial distance = R

d < (R2−R1)

To determine

Express the response using the variables ρE, R1, R2, R3, d, R, and constants

Solution

We have two parallel cylinders

therefore, area equals 2 R × l

And we apply Gauss's Law

EA = Q(enclosed) / ∈o......1

Initially, we calculate Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( R1² × l )

Thus, inserting all values into equation 1

produces

EA = Q(enclosed) / ∈o

E(2 R × l)  = ρ ( R1² × l ) / ∈o

This simplifies to

E =  ρ ( R1²) / 2 ∈o R

The heat required to raise the temperature of a substance by is represented by

where m stands for the mass of the substance and indicates the specific heat of the substance. In this situation, we possess and , the specific heat of water.
Consequently, we can ascertain the temperature rise :

Initially, the water's temperature was , so the end temperature should be

Thus, the water is expected to be vapor by now.

However, to give a more accurate statement, during the liquid to vapor transition, the heat added to the system is used to break molecular bonds instead of raising the system's temperature. The heat necessary for the phase change from liquid to vapor is expressed as

where denotes the latent heat of vaporization for water.
Nevertheless, the initial heat input of 50 KJ is less than this requirement, indicating there isn't sufficient heat to finish the liquid-vapor transition. Therefore, the water will remain in the liquid-vapor change phase at a temperature of (the temperature at which the phase change begins)

Answer:

1.5 × 10³⁶ light-years

Explanation:

A particular square area in interstellar space measures roughly 2.4 × 10⁷² (light-years)². To find the area of a square, the following formula is utilized:

A = l²

where,

A represents the area of the square

l denotes the length of one side of the square

Thus, l = √A = √2.4 × 10⁷² (light-years)² = 1.5 × 10³⁶ light-years

Both snowballs will land with the same speed. Explanation: For snowball A, the initial velocity is 13 m/sec and it experiences gravitational acceleration. According to Newton's third law, we find the final velocity of snowball A to be 17.5 m/sec. For snowball B, with an initial speed of 13 m/sec projected at an angle of 25°, we can deduce both horizontal and vertical components of velocity. Therefore, upon landing, both snowballs will retain equal speed.

Answer:

Speed = 0.296m/2

Period = 0.203 s

Explanation:

If by 'long' you're referring to the waves' wavelength, then the wavelength .

The waves have a frequency of 14.8 cycles every 3 seconds, or

.

The interplay between the wavelength , frequency , and speed of the waves is defined as:

We input the values and leading to:

To determine the period , one simply calculates the inverse of the frequency, or