What is 7/2 mm x 14/5 mm

Given that ∠ABC is an inscribed angle, we need to determine the measures of ∠BDA and ∠BCA. To begin, we first calculate the central angle ∠BOA, which corresponds to the intercepted arc measure of BA: ∠BOA = 360° - 250° = 110°. Thus, the intercepted arc AB measures 110°. Applying the relevant formulas: ∠BDA = 55°. Next, we find ∠BCA. In the quadrilateral AOBC, with AC and BD being tangents, we know that ∠CAO = 90° and ∠CBO = 90°. Since the sum of angles in a quadrilateral is 360°, we set up the equation ∠AOB + ∠CAO + ∠CBO + ∠BCA = 360°. Substituting known values, we find ∠BCA = 360° - 290°, yielding ∠BCA = 70°. Thus, the proof is completed.

Answer:

1458/3456 reduces to 27/64 (after simplification)

The cube root of 27/64 equals 3/4

The square of 3/4 calculates to 9/16

Multiplying 9/16 by 1024 results in 576.

THIS IS THE ACTUAL WORK AND RESULT

Please make me brainliest

Answer:

A) Maia had 1920 beads more.

B) Maia had 2544 beads at first.

Step-by-step analysis:

Let x denote the beads with Jenny and y for Maia.

The information provided states that Maia possesses 2064 beads more than Jenny, which can be represented mathematically as:

Additionally, after Maia made a necklace with 144 beads, she had five times more beads than Jenny.

This can also be formulated as an equation:

A) Since Maia had 2064 beads more than Jenny before using 144 beads, we calculate her final bead count by subtracting 144 from 2064.

Thus, Maia is left with 1920 beads more than Jenny.

B) To solve this system of linear equations, we will utilize the substitution method.

By inserting equation (1) into equation (2), we arrive at:

Now, let's divide our equation by 4.

Now, we'll substitute x=480 into equation (1) to isolate y.

Conclusively, Maia initially had 2544 beads.