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cupoosta
16 days ago
14

The two containers are mathematically similar in shape. The larger container has a volume of 3456cm3 and a surface area of 1024c

m2. The smaller container has a volume of 1458cm3. Calculate the surface area of the smaller container.
Mathematics
1 answer:
zzz [9K]16 days ago
4 0

Answer:

1458/3456 reduces to 27/64 (after simplification)

The cube root of 27/64 equals 3/4

The square of 3/4 calculates to 9/16

Multiplying 9/16 by 1024 results in 576.

THIS IS THE ACTUAL WORK AND RESULT

Please make me brainliest

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William has 32 coins that are all either quarters or dimes. The coins have a value of $5.00. How many dimes does William have?
Svet_ta [9500]

Answer:

Step-by-step explanation:

d + q = 32

.10d +.25q = 5.00

d + q = 32

10d + 25q = 500

-10d - 10q = -320

 10d + 25q = 500

15q = 180

q= 12 quarters

d + 12 = 32

d = 20 dimes

5 0
2 days ago
At a hot air ballon festival, Erica spots a red ballon due east at an angle of elevation of 36 degrees. She turns due west and s
Zina [9171]

Answer:

Step-by-step explanation:

Information provided

The eastern balloon makes an elevation angle of 36^{\circ} and is positioned at a height of 461 m.

The western balloon creates an elevation angle of 51^{\circ} and is positioned at a height of 296 m.

Considering that Erica is 1.6 m tall, the effective height of the Red balloon becomes 459.4 m,

while the effective height of the Blue balloon ends up at 294.4 m.

Utilizing trigonometric principles,

\tan 36=\frac{459.4}{d_1}

\tan 51=\frac{294.4}{d_2}

d_1=632.30 m

d_2=238.4 m

Now calculating the distance separating the two Balloons,

d=d_1+d_2

d=870.70 m

7 0
20 days ago
The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin
PIT_PIT [9117]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

The details provided in the question are:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

The weights are distributed in a bell-shaped normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We need to determine the value of x for which the probability is 0.03.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03  

=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97  

Using the standard normal z table, we find that,

\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12  

Thus, the value of 8.17 g separates the upper 3% of the weights.

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03  

From the standard normal z table, we derive,

\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90  

Consequently, 7.90 separates the lower 3% of the weights.

<ptherefore the="" accurate="" answer="" is="">

Option D) 7.90 g and 8.12 g

</ptherefore>
7 0
16 days ago
Solve for x<br> zx=5g(2x-c)
Leona [9271]
Zx = 5g(2x - c) Apply the Distributive Property
zx = 10gx - 5cg Subtract 10gx from each side
zx - 10gx = -5cg Factor x out
x (z - 10g) = -5cg Divide by (z - 10g)
x = \frac{-5cg}{z - 10g}
3 0
1 month ago
Read 2 more answers
A survey of 100 people found that 35 people exercise in the morning, 45 people exercise in the afternoon, and 20 people exercise
Zina [9171]
Out of 100 surveyed individuals, 35 work out in the morning, 45 in the afternoon, and 20 at night.

Jim is accurate.....
The ratio of morning exercisers to the whole group is 35/100.
The ratio of afternoon exercisers is 45/100.
The ratio for night exercisers is 20/100.
7 0
26 days ago
Read 2 more answers
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