To solve this problem, you'll want to substitute the first equation into the second or the other way around. The equations given are: 1. 3 paperback books + 5 hardcover books = $80.10; 2. 7 paperback books + 4 hardcover books = $100.65. It is helpful to rearrange the first equation to find 5 hardcover books = $80.10 - 3 paperback books, leading to hardcover book = $16.02 - 0.6 paperback books. Now, substitute this into the second equation: 7 paperback books + 4 ($16.02 - 0.6 paperback books) = $100.65, which simplifies to 7 paperback books + $64.08 - 2.4 paperback books = $100.65. This results in 4.6 paperback books = $100.65 - $64.08 = $36.57, thus paperback book = $7.95. You can then use this price in the first equation to determine the hardcover book price: 3 paperback books + 5 hardcover books = $80.10, substituting gives 3($7.95) + 5 hardcover books = $80.10, which leads to 5 hardcover books = $80.10 - $23.85 = $56.25, therefore hardcover book = $11.25. Hence, the total cost for one paperback and one hardcover book is $7.95 + $11.25 = $19.20.
Answer:
CrO₃.
Step-by-step explanation:
First, we will find the chromium percentage in the oxide by using the following process:
Oxygen (O) = 48%
Chromium (Cr) =?
The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:
Cr = 100 – percentage of oxygen
Cr = 100 – 48
Cr = 52%
Next, we will determine the empirical formula for the oxide:
Chromium (Cr) = 52%
Oxygen (O) = 48%
Now, we divide by their molar mass:
Cr = 52/52 = 1
O = 48/16 = 3
Now, divide by the lowest value:
Cr = 1/1 = 1
O = 3/1 = 3
Thus, the empirical formula for the oxide is CrO₃.
There are seven rainbow colors: red, orange, yellow, green, blue, indigo, and violet, so 7 possible choices. When two events occur in sequence, multiply their probabilities. With replacement: P(violet)=1/7 and P(orange)=1/7, so P(violet then orange)=1/7 * 1/7 = 1/49. Without replacement: after picking violet, P(orange)=1/6, so P(violet then orange)=1/7 * 1/6 = 1/42.
...z........................
Let’s consider the curve: r(t) = t²i +(int)j + 1/t k
X = t², y = int,z = 1/t
Utilizing x = t² and z = 1/t
X = (1/z)²
Xz² = 1
Now using y = int and z= 1/t
Y = in│1/z│
By using x = t² and y = int
Y = int = in(√x)
Thus, the resulting surfaces are,
Xz² = 1
Y = in│1/z│
Y= in(√x)
